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Q: A 3-digit number a square number and the product of its digits is 2?

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5.5

A square number is the product you get when you multiply a number by itself.

A square number is the product of a number and itself. 16 is square; it is the product of 4 and 4; 4 times 4.

16

64

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81

121

225 = (15)2 2*2*5=20 3 digits in 225

121 because 2x1x1=2 and 11x11=121

The number of digits in the square root of a number depends on the number. If it is a square number, the square root will have a finite number of digits. If the number is not a square number then the square root will be an irrational number with an infinite, non-repeating decimal representation. In both cases, the number of digits before the decimal point, in the square root of x will be the rounded value of 1+0.5*log10(x)

I cannot see how odd or even will determine the number of digits in the square root. For example:100 is an even number, and its square root is 10 (2 digits)121 is an odd number, and its square root is 11 (2 digits)Maybe the question is not phrased properly for what the questioner is asking.

121 121 = 11^2 1 x 2 x 1 = 2

5.5

I/you/we am 49

1225 = 352.

A square number is the product you get when you multiply a number by itself.

A square number is the product of the same two integers. A rectangular number is the product of consecutive integers.

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