As a product of its prime factors: 3*5*7 = 105
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Take the 'reciprocal' of the given scale factor to go the other way. The 'reciprocal' of a number is 1/(the number). 3 ==> 1/3 5 ==> 1/5 1/7 ==> 7 2/3 ==> 3/2 etc.
This is a LCM question, so factor all and find the highest power of each prime factor. 2 is prime 3 is prime 5 is prime 6 is [2 3] 7 is prime. LCM is [2] [3] [5] [7] so the answer is 210◄
The least common factor of 2, 3, 4, 5, 6, 7, 8, 9, and 10 is 1.The least (or lowest) factor that any of these numbers has is 1.The least (or lowest) number in the list is 2.
all perfect cubes (any number powered by 3) by adding or subtracting 1 become factor of 7 except base number as 7 and its factors.
21 has 3 as a factor and is a multiple of 7, and so as 210, 105, and an infinite number of other numbers.