As a product of its prime factors: 3*5*7 = 105
Take the 'reciprocal' of the given scale factor to go the other way. The 'reciprocal' of a number is 1/(the number). 3 ==> 1/3 5 ==> 1/5 1/7 ==> 7 2/3 ==> 3/2 etc.
This is a LCM question, so factor all and find the highest power of each prime factor. 2 is prime 3 is prime 5 is prime 6 is [2 3] 7 is prime. LCM is [2] [3] [5] [7] so the answer is 210◄
The least factor of any number is always 1. Therefore, the least factor of 2, 3, 4, 5, 6, 7, 8, 9, and 10 is 1.
all perfect cubes (any number powered by 3) by adding or subtracting 1 become factor of 7 except base number as 7 and its factors.
21 has 3 as a factor and is a multiple of 7, and so as 210, 105, and an infinite number of other numbers.
420
Factoring each number into product of primes: 5=1 x 5 7 = 1 x 7 9 = 3 x 3, 1 x 9 The number 5 is a factor of 5 only; Include 5 in answer The number 7 is a factor of 7 only; Include 7 in answer The number 3 is a factor twice of 9; Include 3x3 in answer Therefore, LCM(5,7,9) = 3 x 3 x 5 x 7 = 315 Additional content regarding LCM may be referenced at http://www.math.info/Arithmetic/LCM
It is: 2*3*5*7*11 = 2310
3 x 5 x 7 x 7 = 735
A factor of a number is an integer that divides the number evenly (without remainder). So 2 and 3 are factors of 12 (12/2 is 6 and 12/3 is 4), but 7 is not a factor of 12 (12/7 is 1 remainder 5). 2 and 3 are not factors of 5 (notice 5 is prime).
3 x 5 x 7 = 105
There is only one common factor of 5, 3, 7: 1
Take the 'reciprocal' of the given scale factor to go the other way. The 'reciprocal' of a number is 1/(the number). 3 ==> 1/3 5 ==> 1/5 1/7 ==> 7 2/3 ==> 3/2 etc.
Since the number ends with 5, 5 is a factor. 3 is also a factor. Divide it by those factors, then see if you can find additional factors.
A factor tree tells you the prime factorization. The prime factorization can indicate a square number. Square numbers have even pairs of prime factors. 2 x 2 x 3 x 3 is a square number. 5 x 5 x 5 x 5 x 7 x 7 x 7 x 7 is a square number.
This is a LCM question, so factor all and find the highest power of each prime factor. 2 is prime 3 is prime 5 is prime 6 is [2 3] 7 is prime. LCM is [2] [3] [5] [7] so the answer is 210◄
d. 3