1,215
A number is divisible by 27 if it can be expressed as 27 multiplied by an integer. This means any multiple of 27, such as 27, 54, 81, and so on, is divisible by 27. Additionally, for larger numbers, you can check divisibility by summing the digits of the number and confirming if that sum is divisible by 27.
No,because 45 is not divisible by both 2 and 3. In order for a number to be divisible by 6 it has to be divisible by both 2 and 3.
45
The number 9 is the smallest, but there are an infinite number of answers to the question. 15, 21, 27, 33, 39, and 45 are some more.
A 4-digit number divisible by both 5 and 9 must be divisible by their least common multiple, which is 45. To find a 4-digit number divisible by 45, we need to find a number that ends in 0 and is divisible by 45. The smallest 4-digit number that fits these criteria is 1005 (45 x 22 = 990, and adding 15 gives us 1005).
No,because 45 is not divisible by both 2 and 3. In order for a number to be divisible by 6 it has to be divisible by both 2 and 3.
A number is divisible by 27 if it can be expressed as 27 multiplied by an integer. This means any multiple of 27, such as 27, 54, 81, and so on, is divisible by 27. Additionally, for larger numbers, you can check divisibility by summing the digits of the number and confirming if that sum is divisible by 27.
45/5 = 9 45/9 = 5 Therefore, the smallest number divisible by both numbers is 45.
45
Sum the digits in blocks of three from right to left. If the result is divisible by 27, then the number is divisible by 27
The number 9 is the smallest, but there are an infinite number of answers to the question. 15, 21, 27, 33, 39, and 45 are some more.
135 135 / 3 = 45 135 / 5 = 27
A 4-digit number divisible by both 5 and 9 must be divisible by their least common multiple, which is 45. To find a 4-digit number divisible by 45, we need to find a number that ends in 0 and is divisible by 45. The smallest 4-digit number that fits these criteria is 1005 (45 x 22 = 990, and adding 15 gives us 1005).
45% of 27 = 45% * 27 = 0.45 * 27 = 12.15
9
No. 135 is divisible by: 1, 3, 5, 9, 15, 27, 45, 135.
The number that is between 40 and 50 and is divisible by both 3 and 5 is 45. To determine if a number is divisible by both 3 and 5, you must ensure it is divisible by both 3 and 5 without leaving a remainder. In this case, 45 meets this criteria as it is divisible by both 3 (45 ÷ 3 = 15) and 5 (45 ÷ 5 = 9).