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What numbers a divisible by 27?

A number is divisible by 27 if it can be expressed as 27 multiplied by an integer. This means any multiple of 27, such as 27, 54, 81, and so on, is divisible by 27. Additionally, for larger numbers, you can check divisibility by summing the digits of the number and confirming if that sum is divisible by 27.


Is 45 divisible by 6?

No,because 45 is not divisible by both 2 and 3. In order for a number to be divisible by 6 it has to be divisible by both 2 and 3.


What is the smallest number divisible by 5 and 9?

45/5 = 9 45/9 = 5 Therefore, the smallest number divisible by both numbers is 45.


What number is divisible by 15 and also divisible by 9 What is the smallest possible number?

45


What is the number that is divisible by 3 and not 2?

The number 9 is the smallest, but there are an infinite number of answers to the question. 15, 21, 27, 33, 39, and 45 are some more.


What number between 121 and 149 is divisible by 3 and 5?

135 135 / 3 = 45 135 / 5 = 27


What is the divisibility rule for the number 27?

Sum the digits in blocks of three from right to left. If the result is divisible by 27, then the number is divisible by 27


What is a 4 digit number divisible by five and nine?

A 4-digit number divisible by both 5 and 9 must be divisible by their least common multiple, which is 45. To find a 4-digit number divisible by 45, we need to find a number that ends in 0 and is divisible by 45. The smallest 4-digit number that fits these criteria is 1005 (45 x 22 = 990, and adding 15 gives us 1005).


What number is 45 percent of 27?

45% of 27 = 45% * 27 = 0.45 * 27 = 12.15


Is 135 divisible by 10?

No. 135 is divisible by: 1, 3, 5, 9, 15, 27, 45, 135.


What number is 27 divisible by?

9


What is the divisibility rule for 27?

Subtract 8 times the last digit from remaining truncated number. Repeat the step as necessary. If the absolute of result is divisible by 27, the original number is also divisible by 27 Check for 945: 94-(8*5)=54; 5-(8*4)=-27 Since 27 is divisible by 27, the original no. 945 is also divisible. Check for 264681: 26468-(8*1)=26460; 2646-(8*8)=2582; 264-(8*6)=216 21-(8*6)=-27 Since 27 is divisible by 27, the original no. 264681 is also divisible. Check for 81: 8-(8*1)=0; Since 0 is divisible by 27, the original no. 81 is also divisible.