9
Sum the digits in blocks of three from right to left. If the result is divisible by 27, then the number is divisible by 27
Subtract 8 times the last digit from remaining truncated number. Repeat the step as necessary. If the absolute of result is divisible by 27, the original number is also divisible by 27 Check for 945: 94-(8*5)=54; 5-(8*4)=-27 Since 27 is divisible by 27, the original no. 945 is also divisible. Check for 264681: 26468-(8*1)=26460; 2646-(8*8)=2582; 264-(8*6)=216 21-(8*6)=-27 Since 27 is divisible by 27, the original no. 264681 is also divisible. Check for 81: 8-(8*1)=0; Since 0 is divisible by 27, the original no. 81 is also divisible.
1,215
972 is one of the numbers that is divisible by both.
No remainder. It has the same rule as 3 for divisibility. Add them up and if that is divisible by 27 then the number is divisible by 27.
How about 27
81 is divisible by 1, 3, 9, 27 and 81
1080
27, 21
A number is divisible by 3 if the sum of its digits is a multiple of 3. For example, 27 = 2 + 7 = 9/3 = 3. Therefore, 27 is divisible by 3.If the sum of the digits of the number in question is divisible by three, the whole number is divisible by three.
To find the number that can be added to 368 to make it divisible by 27, you need to first determine the remainder when 368 is divided by 27. You can do this by finding the modulus of 368 divided by 27, which is 17. To make 368 divisible by 27, you need to add the difference between 27 and the remainder (27 - 17 = 10). Therefore, you would need to add 10 to 368 to make it divisible by 27.
The easiest way to know if a number is divisible by 9 is to add the digits in the number. 4 + 7 + 8 + 8 = 27 Since 9 will go into 27 evenly, 4788 is divisible by 9.