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What is the probability of rolling a 2 on the roll on a die?
If it's a six-sided die (like the kind used in craps and most dice games) the odds are 1 in 6.The probability of rolling a single number on any kind of die* is 1 ÷ (the number of sides).*Except, of course, for weighted, shaved, or otherwise illegal dice.
What are the Odds of rolling doubles?
Answer 1:The odds are very easy to calculate. Simply divide the number of "valid" rolls against all possible rolls. For ease, you can write down all possible combination for the 2 dice.1-1; 1-2; 1-3; 1-4....and so on, remember 1-4 and 4-1 are different rollsThere are 36 unique possible combination, and 6 of them are doubles, so that's 6/36 chances (and since 6 goes into 36, 6 times, this reduces to 1/6) or about 17%Answer 2:Another way to look at this problem, generically, is to assume we have an 'n' face dice. In most cases, dice have 6 faces (1, 2, 3, 4, 5, 6). But why not create a solution that works for any number of sides? Well, if we are trying to calculate the probability of rolling two dice (dice-1 and dice-2) of 'n' sides at the same time and having them turn up as doubles, only one of the dice really matters. Here's why. Dice-1 is guaranteed to land on a number 1-n. This will happen every time (on a fair dice, disregarding freak incidents). What we are trying to calculate is the probability that dice-2 will land on the SAME number as dice-1. Dice-2 can only land on one of 'n' values: 1, 2, 3, 4, 5, 6, ... , 'n'. For you non math folks, this just means it must land on a number from 1 to 'n' where 'n' is the number of sides on your dice. Out of all of the sides that dice-2 can PHYSICALLY land on, one of the sides MUST necessarily have the same as the value that dice-1 landed on. That is to say, if dice-1 landed on the value 3, there must be some chance that dice-2 will also land on the value 3. The probability of this occurring on a fair die is 1 divided by the total number of possible outcomes, which would be 'n'. So, really, there is a 1/n chance that dice-2 will land on the same number as dice-1. Thus, our probability for rolling doubles is simple 1/n. For our 6 sided dice example, our dice-1 lands on some value between 1 and 6 and there is a 1/6 chance dice-2 will match it.
What is the most likely roll in dice?
Assuming you are only rolling one die, then each of the six numbers (1,2,3,4,5,6) has an equal chance (1 sixth) of landing face up.
Why does a 10 sided dice have 9 for the highest number?
Ten-sided dice are often used in games that require a "percentage roll", such as Dungeons & Dragons. Players roll two 10-sided dice, and the numbers rolled are used as digits to form a number between 0 and 99. Using a "0" instead of "10" simplifies this process. For most other games and instances, zeroes on ten-sided dice represent tens. Just FYI - some ten-sided dice do actually have a "10" instead of a "0", but they're fairly rare. I got 4 of them in a board game called Filthy Rich, which - ironically enough - uses numerous references to rolling zeroes instead of tens. Go figure.
What is the probability of getting one prime number when rolling two dice?
In solving problems like this, the most straightforward approach is to make a table. Columns are used to show the six outcomes from one of the dice, rows the outcomes from the other die. In each cell of the table put the sum of the two dice. Now go throught the table row by row, counting the values that are prime numbers. There are 36 cells in the table, and I counted 15 primes, making a probability of 15/36 = 5/9. But my counting has been wrong before! You had better check it.
What is the probability of rolling a 4 or 5 on a six sided cube?
The chance of rolling a certain number on a dice is 1/6, so the chance of rolling a 4 OR 5is 2/6. But if you have two dice you have the most chance of rolling a seven (6/36 or 1/6)
What number will come up the most when rolling dice?
since there are 6 sides to it any of them could show up, 1,2,3,4,5, and 6 could all show up unlikely
Using 2 dice what is the most least number to roll?
2. This would be as a result of rolling a 1 on each of them.
What is the probability of rolling a 2 on the roll on a die?
If it's a six-sided die (like the kind used in craps and most dice games) the odds are 1 in 6.The probability of rolling a single number on any kind of die* is 1 ÷ (the number of sides).*Except, of course, for weighted, shaved, or otherwise illegal dice.
Using 2 dice what is the most likely number to roll?
AnswerThe most likely number is seven.This can be 1+6, 2+5, 3+4, 4+3, 5+2, 6+1.Remember that dice have no memory - if you have rolled 7 three times in a row the odds of rolling another 7 does not change.this is all wrong don't listen that
What is the expected value of rolling two dice?
The most probable result of rolling two dice is a sum of seven. The probability of rolling a seven is 1 in 6 or about 0.167.All of the other possible sums have decreasing probability, all the way down to 1 in 36 or about 0.0278 for a sum of two or a sum of 12.
Two dice are rolled Find the probability that the score on the dice is either 12 or at most 4?
The problem can be split into two parts, rolling a 12, or rolling a 4 or less. This can be further broken down to rolling a 2, rolling a 3, rolling a 4, or rolling a 12. P(rolling 4 or less, or 12) = P(rolling 4 or less) + P(rolling 12) = P(rolling a 2) + P(rolling a 3) + P(rolling a 4) + P(rolling a 12) = 1/36 + 2/36 + 3/36 + 1/36 = 7/36
Who had most number ones rolling stones or the who?
The who
What are the Odds of rolling doubles?
Answer 1:The odds are very easy to calculate. Simply divide the number of "valid" rolls against all possible rolls. For ease, you can write down all possible combination for the 2 dice.1-1; 1-2; 1-3; 1-4....and so on, remember 1-4 and 4-1 are different rollsThere are 36 unique possible combination, and 6 of them are doubles, so that's 6/36 chances (and since 6 goes into 36, 6 times, this reduces to 1/6) or about 17%Answer 2:Another way to look at this problem, generically, is to assume we have an 'n' face dice. In most cases, dice have 6 faces (1, 2, 3, 4, 5, 6). But why not create a solution that works for any number of sides? Well, if we are trying to calculate the probability of rolling two dice (dice-1 and dice-2) of 'n' sides at the same time and having them turn up as doubles, only one of the dice really matters. Here's why. Dice-1 is guaranteed to land on a number 1-n. This will happen every time (on a fair dice, disregarding freak incidents). What we are trying to calculate is the probability that dice-2 will land on the SAME number as dice-1. Dice-2 can only land on one of 'n' values: 1, 2, 3, 4, 5, 6, ... , 'n'. For you non math folks, this just means it must land on a number from 1 to 'n' where 'n' is the number of sides on your dice. Out of all of the sides that dice-2 can PHYSICALLY land on, one of the sides MUST necessarily have the same as the value that dice-1 landed on. That is to say, if dice-1 landed on the value 3, there must be some chance that dice-2 will also land on the value 3. The probability of this occurring on a fair die is 1 divided by the total number of possible outcomes, which would be 'n'. So, really, there is a 1/n chance that dice-2 will land on the same number as dice-1. Thus, our probability for rolling doubles is simple 1/n. For our 6 sided dice example, our dice-1 lands on some value between 1 and 6 and there is a 1/6 chance dice-2 will match it.
What number shows up most often when you roll 10 dice?
#7
If you roll 2 die and add the 2 numbers together what would be the most likely total?
4
What is the most likely roll in dice?
Assuming you are only rolling one die, then each of the six numbers (1,2,3,4,5,6) has an equal chance (1 sixth) of landing face up.
