divide 216 by 3 (72) subtract 1 and add 1 71, 72 and 73
108, 162, 216 & 270
251
215 + 216 + 217 + 218 = 866
Let the 3 consecutive numbers be (a-1), a, and (a+1) So, (a-1) + (a) + (a+1) = 216 You add the left-hand side and get: 3a =216 You divide and get: a = 216/3 = 72 So, (a-1) = 72-1 = 71 a = 72 (a+1)= 72+1 = 73 Check: 71+72+73 = 216
i do not no
x+x+1+x+2=216 3x+3=216 3x=213 71,72,73
divide 216 by 3 (72) subtract 1 and add 1 71, 72 and 73
108, 162, 216 & 270
251
215 + 216 + 217 + 218 = 866
Let the 3 consecutive numbers be (a-1), a, and (a+1) So, (a-1) + (a) + (a+1) = 216 You add the left-hand side and get: 3a =216 You divide and get: a = 216/3 = 72 So, (a-1) = 72-1 = 71 a = 72 (a+1)= 72+1 = 73 Check: 71+72+73 = 216
the sum of three consecutive numbers is 216. What are the three numbers?
216 = 2x2x2x3x3x3
216
The numbers that can go into 216 1,2,3,4,6,8,9,12,18,24,27,36,54,72,108,216,
As a number: 216,000,000 = 216 million