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How many numbers between 1 and 240 are divisible by 4 and 5?
To be divisible by both 4 and 5, the number has to be divisible by 20. Therefore, there are 12 numbers between 1 and 240, inclusive, which are divisible by 4 and 5: 20, 40, 60, 80, 100, 120, 140, 160, 180, 200, 220, 240.
What are the divisibility rules for 1 2 3 4 5 6 9 and 10?
All whole numbers are divisible by 1. Numbers are divisible by 2 if they end in 2, 4, 6, 8 or 0. Numbers are divisible by 3 if the sum of their digits is divisible by 3. Numbers are divisible by 4 if the last two digits of the number are divisible by 4. Numbers are divisible by 5 if the last digit of the number is either 5 or 0. Numbers are divisible by 6 if they are divisible by 2 and 3. Numbers are divisible by 9 if the sum of their digits is equal to 9 or a multiple of 9. Numbers are divisible by 10 if the last digit of the number is 0.
What numbers are divisible by 2 4 5?
40
How many 4-digit numbers can be formed by the digits 1 2 3 4 5 with repetition is allowed and that are divisible by 4?
125 different 4 digits numbers. To be divisible by 4, the last two digits must be divisible by 4, which means they must be: 12, 24, 32, 44 or 52 - 5 possible choices. For each of these there are 5 choices for the first digit and 5 for the second, meaning: total = 5 x 5 x 5 = 125
What numbers are divisible by 2 3 4 5 and 6?
the lowest number divisalbe by all of them is 6060/2=3060/3=2060/4=1560/5=12
Which numbers have a least common multiple of 12?
Numbers for which the sum of the digits is divisible by 9. This is also true for 3. There are other divisibility/multiple tests for other numbers (e.g., numbers that are divisible by 5 end in 5 or 0; numbers whose last two digits are divisible by 4 are divisible by 4)
How many numbers between 1 and 240 are divisible by 4 and 5?
To be divisible by both 4 and 5, the number has to be divisible by 20. Therefore, there are 12 numbers between 1 and 240, inclusive, which are divisible by 4 and 5: 20, 40, 60, 80, 100, 120, 140, 160, 180, 200, 220, 240.
What 5 numbers are divisible by 4?
...-20, -16, -12, -8, -4, 0, 4, 8, 12, 16, 20,....
All numbers divisible by 4 and 15 are also divisible by what?
They are divisible by 2, 3, 4, 5, 6, 10, 12, 15, 30 and 60 at least.
What is a Venn diagram for numbers divisible by 4 and 5?
A Venn diagram for numbers divisible by both 4 and 5 would have two overlapping circles. One circle would represent numbers divisible by 4, while the other circle would represent numbers divisible by 5. The overlapping region where the two circles intersect would represent numbers divisible by both 4 and 5. This intersection would include numbers that are multiples of both 4 and 5, such as 20, 40, 60, and so on.
Which number is divisible by 5 and 4?
There are infinitely many numbers divisible by 5 and 4. 680 is one of them.
What are the divisibility rules for 1 2 3 4 5 6 9 and 10?
All whole numbers are divisible by 1. Numbers are divisible by 2 if they end in 2, 4, 6, 8 or 0. Numbers are divisible by 3 if the sum of their digits is divisible by 3. Numbers are divisible by 4 if the last two digits of the number are divisible by 4. Numbers are divisible by 5 if the last digit of the number is either 5 or 0. Numbers are divisible by 6 if they are divisible by 2 and 3. Numbers are divisible by 9 if the sum of their digits is equal to 9 or a multiple of 9. Numbers are divisible by 10 if the last digit of the number is 0.
How many numbers are divisible between 17 and 61 are divisible by 8?
There are 5 numbers between 17 and 61 that are divisible by 8. They are 24, 32, 40, 48, and 56.
What numbers are divisible by 3 4 and 5?
Well, honey, the numbers that are divisible by 3, 4, and 5 are called multiples of the least common multiple of 3, 4, and 5, which is 60. So, any number that is a multiple of 60 will be divisible by 3, 4, and 5. Math can be a real party pooper sometimes, but that's just how the cookie crumbles.
What numbers is divisible by 4 5 and 9?
90
What numbers are divisible by 2 4 5?
40
How many 4-digit numbers can be formed by the digits 1 2 3 4 5 with repetition is allowed and that are divisible by 4?
125 different 4 digits numbers. To be divisible by 4, the last two digits must be divisible by 4, which means they must be: 12, 24, 32, 44 or 52 - 5 possible choices. For each of these there are 5 choices for the first digit and 5 for the second, meaning: total = 5 x 5 x 5 = 125
