Numbers that would require regrouping in the ones place when added to 21 are any numbers from 9 to 19. When adding a number in this range to 21, the sum will exceed 30, necessitating regrouping in the ones place to carry over to the tens place. For example, when adding 19 to 21, the sum is 40, requiring regrouping.
Regrouping for addition and multiplication both involve reorganizing numbers to simplify calculations. In addition, regrouping allows us to carry over values when sums exceed ten, while in multiplication, regrouping helps in breaking down larger numbers into more manageable parts, often using the distributive property. Both methods ultimately aim to make the computation process easier and more efficient. Additionally, both techniques highlight the importance of place value in achieving accurate results.
To regroup 1578 - 6000 by regrouping once, we can first think of 6000 as 6000 = 5000 + 1000. Then, we can subtract 5000 from 1578, which requires regrouping since 1578 is less than 5000. By borrowing 1 from the thousands place, we turn 1578 into 6578 (which is 1000 more), allowing us to calculate 6578 - 5000 = 1578. Finally, we subtract the remaining 1000 to get 1578 - 6000 = -4222.
Back in the day, regrouping in addition was called "carrying" and regrouping in subtraction was called "borrowing." I think "regrouping" is a better term for all of it. These problems might be easier to visualize if you copy them vertically. Example: 45 + 28 5 + 8 is 13, which won't fit in the ones place, so we leave 3 of the ones there and regroup the ten other ones into one ten which we add in the tens column. 1 + 4 + 2 = 7 45 + 28 = 73
The only rule is that the place value of each digit is ten times that of the digit to its right. A decimal representation does not require a decimal point.
Back in the day, regrouping in addition was called "carrying" and regrouping in subtraction was called "borrowing." I think "regrouping" is a better term for all of it. These problems might be easier to visualize if you copy them vertically. Example: 56 - 39 Just looking at it, you might think there's a problem with subtracting nine from six until you realize that 56 is 5 tens and 6 ones which is the same thing as 4 tens and 16 ones. Now you can subtract 9 from 16, leaving 7 in the ones place and 3 from 4, (the regrouped 5) leaving 1 in the tens place. 56 - 39 = 17 Example: 45 + 28 5 + 8 is 13, which won't fit in the ones place, so we leave 3 of the ones there and regroup the ten other ones into one ten which we add in the tens column. 1 + 4 + 2 = 7 45 + 28 = 73
EXAMPLE: 24+2= 26 NO REGROUPING 56+3=59 NO REGROUPING 24+8=32 IS REGROUPING 56+4=60 IS REGROUPING TAKING THE ONES PLACE ONLY: FIRST EXAMPLE 4+2=6 HAS TO BE LESS THAN 9 4+8=12 YOU MAKE 10 IN THE ONES PLACE YOU CARRY OVER WHICH NOW THEY ARE CALLING REGROUPING. WE JUST CALLED IT CARRYING OVER AND BORROWING. HOPE THIS HELPS.
I take this question to mean what number when added to 457 will yield 999. In this case it is 542.
Ah, what a wonderful question! The word you're looking for is "regrouping." When we regroup in math, we move values between place values to make exchanging equal amounts easier. It's like rearranging puzzle pieces to create a beautiful picture of numbers. Just remember, there are no mistakes in math, only happy little accidents!
Back in the day, regrouping in addition was called "carrying" and regrouping in subtraction was called "borrowing." These problems might be easier to visualize if you copy them vertically. Example: 56 - 39 Just looking at it, you might think there's a problem with subtracting nine from six until you realize that 56 is 5 tens and 6 ones which is the same thing as 4 tens and 16 ones. Now you can subtract 9 from 16, leaving 7 in the ones place and 3 from 4, (the regrouped 5) leaving 1 in the tens place. 56 - 39 = 17
Regrouping
To regroup 1578 - 6000 by regrouping once, we can first think of 6000 as 6000 = 5000 + 1000. Then, we can subtract 5000 from 1578, which requires regrouping since 1578 is less than 5000. By borrowing 1 from the thousands place, we turn 1578 into 6578 (which is 1000 more), allowing us to calculate 6578 - 5000 = 1578. Finally, we subtract the remaining 1000 to get 1578 - 6000 = -4222.
Because the number of digits after the decimal place in a product does not require that.
You might need to regroup more than once when performing multi-digit addition or subtraction, especially when the sum or difference of two numbers exceeds the place value of the column you are working in. For example, when adding numbers like 456 and 378, regrouping may be required in both the tens and hundreds columns. Similarly, when subtracting numbers like 804 and 297, regrouping may be necessary multiple times to ensure accurate results.
Back in the day, regrouping in addition was called "carrying" and regrouping in subtraction was called "borrowing." I think "regrouping" is a better term for all of it. This problem might be easier to visualize if you copy it vertically. Example: 45 + 28 5 + 8 is 13, which won't fit in the ones place, so we leave 3 of the ones there and regroup the ten other ones into one ten which we add in the tens column. 1 + 4 + 2 = 7 45 + 28 = 73
Back in the day, regrouping in addition was called "carrying" and regrouping in subtraction was called "borrowing." I think "regrouping" is a better term for all of it. These problems might be easier to visualize if you copy them vertically. Example: 45 + 28 5 + 8 is 13, which won't fit in the ones place, so we leave 3 of the ones there and regroup the ten other ones into one ten which we add in the tens column. 1 + 4 + 2 = 7 45 + 28 = 73
The only rule is that the place value of each digit is ten times that of the digit to its right. A decimal representation does not require a decimal point.
To subtract 316 from 624, you need to regroup twice. Start by subtracting 6 from 4 in the ones place, which requires regrouping from the tens place. Then, subtract 1 from 2 in the tens place, which also requires regrouping from the hundreds place. Finally, subtract 3 from 5 in the hundreds place to get the final result of 308.