A B-36, the WW-2 vintage heavy bomber, has 30 meters on the pilot's instrument panel.
If an object travels at an average speed of 31 meters per second, you can calculate the distance it would cover in 30 seconds using the formula: distance = speed × time. Thus, distance = 31 meters/second × 30 seconds = 930 meters. Therefore, the object would travel 930 meters in 30 seconds.
IF it started out from rest, then V = a t = (7.8 x 30) = 234 meters per secondin the direction of the acceleration, at the end of 30 seconds.
-2.33 metres per second squared
To calculate the pressure on an object at a depth of 30 meters underwater, you can use the formula: pressure = depth × density of the fluid × gravitational acceleration. The density of water is approximately 1000 kg/m³, and gravitational acceleration is about 9.81 m/s². At 30 meters deep, the pressure due to the water column is approximately 30,000 Pascals (Pa) or 30 kPa, plus atmospheric pressure (around 101.3 kPa at sea level), resulting in a total pressure of about 131.3 kPa on the object. The area of the object (9 sq cm) does not affect the pressure but will influence the total force acting on it.
30 x 30 = 900 2 plots = 1800 square meters
If an object travels at an average speed of 31 meters per second, you can calculate the distance it would cover in 30 seconds using the formula: distance = speed × time. Thus, distance = 31 meters/second × 30 seconds = 930 meters. Therefore, the object would travel 930 meters in 30 seconds.
IF it started out from rest, then V = a t = (7.8 x 30) = 234 meters per secondin the direction of the acceleration, at the end of 30 seconds.
2.38 seconds.
30 meters is the same as 30 linear meters.
-2.33 metres per second squared
To calculate the pressure on an object at a depth of 30 meters underwater, you can use the formula: pressure = depth × density of the fluid × gravitational acceleration. The density of water is approximately 1000 kg/m³, and gravitational acceleration is about 9.81 m/s². At 30 meters deep, the pressure due to the water column is approximately 30,000 Pascals (Pa) or 30 kPa, plus atmospheric pressure (around 101.3 kPa at sea level), resulting in a total pressure of about 131.3 kPa on the object. The area of the object (9 sq cm) does not affect the pressure but will influence the total force acting on it.
The work is 347 joules.
The total displacement is 30 meters South. Displacement is the difference between the initial and final positions of an object, irrespective of the path taken. In this case, the person returns partially to the initial position after moving North by 50 meters.
The kinetic energy of the object at rest on the edge of the cliff is zero because there is no motion.
30 x 30 = 900 2 plots = 1800 square meters
There are about 1181.1 inches in 30 meters.
Potential Energy The object is not in movement.