A B-36, the WW-2 vintage heavy bomber, has 30 meters on the pilot's instrument panel.
If an object travels at an average speed of 31 meters per second, you can calculate the distance it would cover in 30 seconds using the formula: distance = speed × time. Thus, distance = 31 meters/second × 30 seconds = 930 meters. Therefore, the object would travel 930 meters in 30 seconds.
IF it started out from rest, then V = a t = (7.8 x 30) = 234 meters per secondin the direction of the acceleration, at the end of 30 seconds.
-2.33 metres per second squared
30 x 30 = 900 2 plots = 1800 square meters
30 meters = 32.808399 yards
If an object travels at an average speed of 31 meters per second, you can calculate the distance it would cover in 30 seconds using the formula: distance = speed × time. Thus, distance = 31 meters/second × 30 seconds = 930 meters. Therefore, the object would travel 930 meters in 30 seconds.
IF it started out from rest, then V = a t = (7.8 x 30) = 234 meters per secondin the direction of the acceleration, at the end of 30 seconds.
30 meters is the same as 30 linear meters.
2.38 seconds.
-2.33 metres per second squared
The work is 347 joules.
The total displacement is 30 meters South. Displacement is the difference between the initial and final positions of an object, irrespective of the path taken. In this case, the person returns partially to the initial position after moving North by 50 meters.
The kinetic energy of the object at rest on the edge of the cliff is zero because there is no motion.
30 x 30 = 900 2 plots = 1800 square meters
There are about 1181.1 inches in 30 meters.
Potential Energy The object is not in movement.
900 meters/30 seconds = 30 meters/second