It is 50.
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X + (X + 1) + (X + 2) = 156 3X + 3 = 156 3X = 153 X = 51 51 + 52 + 53 = 156 156 = 156 51, 52, 53 ------------------are your three consecutive integers
Two consecutive integers which multiply together to equal 156 are 12 and 13.
You need to look for 2 numbers which have a product of 156 and a difference of 1. First 156 can be written as a product of it's prime factors: 156 = 22 x 3 x 13. From this you can see that 22 x 3 = 12 and hence 12 x 13 = 156.
13 and 12 are the two integers that have the product of 156 and 12 is the smaller of the two.
Let's denote the smallest of the three consecutive numbers as "x". The second number would then be x+1, and the third number would be x+2. Since the sum of the three numbers is 156, we can set up the equation as x + (x+1) + (x+2) = 156. Simplifying the equation, we get 3x + 3 = 156. Solving for x, we find that the smallest number is x = 51.