It is 50.
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X + (X + 1) + (X + 2) = 156 3X + 3 = 156 3X = 153 X = 51 51 + 52 + 53 = 156 156 = 156 51, 52, 53 ------------------are your three consecutive integers
Two consecutive integers which multiply together to equal 156 are 12 and 13.
You need to look for 2 numbers which have a product of 156 and a difference of 1. First 156 can be written as a product of it's prime factors: 156 = 22 x 3 x 13. From this you can see that 22 x 3 = 12 and hence 12 x 13 = 156.
Let's denote the smallest of the three consecutive numbers as "x". The second number would then be x+1, and the third number would be x+2. Since the sum of the three numbers is 156, we can set up the equation as x + (x+1) + (x+2) = 156. Simplifying the equation, we get 3x + 3 = 156. Solving for x, we find that the smallest number is x = 51.
13 and 12 are the two integers that have the product of 156 and 12 is the smaller of the two.