X+(x+1)+(x+2)=3x+3=156
156-3=153
3x=153
153/3=51
The numbers are 156 and 157.
12 & 13
X + (X + 1) + (X + 2) = 156 3X + 3 = 156 3X = 153 X = 51 51 + 52 + 53 = 156 156 = 156 51, 52, 53 ------------------are your three consecutive integers
Let the middle number of the three be n. Then the three consecutive numbers are n-1, n, n+1. Their sum is n-1 + n + n+1 = 3n Their average is 3n / 3 = n The difference between their sum and their average is 3n-n = 2n 2n = 156 => n = 78. Thus the three numbers are 77, 78, 79
12 and 13
The numbers are 51, 52 and 53.
let the three numbers be: n-1, n, n+1 their sum is equal to 3n 468=3n which means that n=156 the three numbers are 155, 156, 157
The numbers are 156 and 157.
12 & 13
X + (X + 1) + (X + 2) = 156 3X + 3 = 156 3X = 153 X = 51 51 + 52 + 53 = 156 156 = 156 51, 52, 53 ------------------are your three consecutive integers
Let the middle number of the three be n. Then the three consecutive numbers are n-1, n, n+1. Their sum is n-1 + n + n+1 = 3n Their average is 3n / 3 = n The difference between their sum and their average is 3n-n = 2n 2n = 156 => n = 78. Thus the three numbers are 77, 78, 79
12 and 13
156
You need to look for 2 numbers which have a product of 156 and a difference of 1. First 156 can be written as a product of it's prime factors: 156 = 22 x 3 x 13. From this you can see that 22 x 3 = 12 and hence 12 x 13 = 156.
54 and 56
It is 50.
Oh, dude, that's like asking me to do math on the spot! Okay, so if we're talking about two consecutive room numbers, we'd be looking at the square root of 156, which is around 12.49. So, the two consecutive room numbers would be 12 and 13 because 12 times 13 equals 156. Math and comedy, who knew they'd go so well together?