The solution set for a linear equation in two variables comprises an infinite number of ordered pairs, and these are defined by the equation that appears in the question!
8x - 7 = 15 + 19xsubtract 19x from both sidesadd seven to both sides8x -19x = 15 +7-11x = 22divide both sides by -11x = -2
x=-2
I don't believe it is a solution.
19x = 36 Therefore, x = 36/19 x = 1.894736842105263157 recurring (that is, 1.894736842105263157894736842105263157...)
-1-2x-4x=19-6x-1 = -19x = 3
19x = 437 x = 437 ÷ 19 x = 23
152
have changed your equation from 19x=29 mod16 to 19x=16 mod29 as it is impossible to have 29 mod 16 in modular arithmetic/it makes no sense. Anyway, any modular equation a=b mod m can be rewritten as a-b=km where k is an integer. or in other words, m divides a-b without remainder. Applying this to the equation above we get (19x-16)/29=k. Now just stick it into a calculator and replace x with integers until the equation gives out an integer, in this case x turns out to be 10.
19x = 437 x = 437 ÷ 19 x = 23
The solution set for a linear equation in two variables comprises an infinite number of ordered pairs, and these are defined by the equation that appears in the question!
-49
8x - 7 = 15 + 19xsubtract 19x from both sidesadd seven to both sides8x -19x = 15 +7-11x = 22divide both sides by -11x = -2
x=-2
I don't believe it is a solution.
To find the value that, when multiplied by 19, equals 114, you would divide 114 by 19. The result is 6, meaning that 6 times 19 equals 114. This can be verified by multiplying 6 by 19 to get 114.
-171 = 19x so x = -9