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have changed your equation from 19x=29 mod16 to 19x=16 mod29 as it is impossible to have 29 mod 16 in modular arithmetic/it makes no sense.
Anyway, any modular equation a=b mod m can be rewritten as a-b=km where k is an integer. or in other words, m divides a-b without remainder. Applying this to the equation above we get (19x-16)/29=k. Now just stick it into a calculator and replace x with integers until the equation gives out an integer, in this case x turns out to be 10.
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How you get 16 MOD 2 equals 0?
MOD (or modulus) gives the remainder when the first number is divided by the second. The remainder of 16 divided by 2 is 0, so 16 MOD 2 = 0.
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4x = 16Divide each side of the equation by 4:x = 4
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It equals postive 16 for more of these prombles go to uglymath.com thank you you ask it I solve it :p
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MOD (or modulus) gives the remainder when the first number is divided by the second. The remainder of 16 divided by 2 is 0, so 16 MOD 2 = 0.
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x = -8
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20
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You can solve your algebra question like this: Example; n+6=16. You are going to need to find out what the N equals to. __+6=16 So you need to find out what the N equals to. You can also solve it like this: 16-6=10. So, 10 is the answer to the equation.
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h = 63
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m=16, n=2
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To solve this equation:set it out as: x-16 = 14add 16 to both sides, so that x is left on its own: x = 16 + 14answer: x = 30
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Solve using the quadratic formula
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16
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-4x-4 equals -16. Add 4 to both sides; -4x equals -12. Divide both sides by -4; x equals 3.
How do you solve 37 percent 16 equals J?
J = 5.92 J = 37% of 16 = 16 * (37/100) = 5.92
