The place value of the digit to the left is ten times greater.
The digit 6 is 1,000 times greater than the value of the 4.
The place value of each digit is b times the place value of the digit to its right where b is the base for the system: whether that is binary, octal, decimal, duodecimal, hexadecimal, sexagesimal or some other value.
10
420 is greater in value than 402. This is due to the fact that a digit in the tens place is ten times as great as a digit in the ones place.
1 trillion, 10 trillion, 100 trillion, 1 quadrillion, etc.
I guess you mean the place value column to the left of a trillion: ten trillion
a trillion
700 sevenhundred
greater than means when the # is bigger in place value. equal to means the # is the same as the other #
The place value of the digit to the left is ten times greater.
No, 0.10 is not greater than 0.14. When comparing decimals, you look at the place value of each digit starting from the left. In this case, the tenths place value is the first decimal place. Since 0.14 has a larger value in the tenths place than 0.10, it is greater.
There is only one number, so I assume the question refers to the first three DIGITS of the number. 980 trillion or 9 * hundred trillion 8 * ten trillion 0 * trillion
A number such as the one you wrote doesn't have a "place-value"; the concept of "place-value" applies to each of the digits. The right-most digit has a place-value of 1, the second digit (from the right) has a place-value of 10, the third one has a place-value of 100 (10 squared), the next one has a place-value of 1000 (10 cubed), etc.
They both place a greater value on what the other has.
0.53 is greater, remember your place value
It is the thousands place.