The smallest three-digit number divisible by the first three prime numbers (2, 3, and 5) and the first three composite numbers (4, 6, and 8) is 120.
in the last three numbers
One hundred forty million is written as 140,000,000 in numbers. This number is composed of three sets of three digits separated by commas to indicate the magnitude of each group. The first set of three digits represents the millions place value, followed by the thousands and units place values.
The three consecutive whole numbers you are looking for are 1, 2, and 3. The sum of the first two numbers, 1 + 2 = 3.
Assessors Parcel Number = APN the first set of numbers is the book #
Then you have a tie, for either first place or last place.
the answer is 120 because the first three prime numbers are 2,3,5 and the first three composite numbers are 4,6,8.
The first three prime numbers are 2,3 and 5.
The smallest three-digit number divisible by the first three prime numbers (2, 3, and 5) and the first three composite numbers (4, 6, and 8) is 120.
120
the sum of the first three numbers is 1 + 3+5= 9
403
in the last three numbers
product = 6 first three positive counting numbers = 1, 2, 3product of the first three positive counting numbers:1 x 2 x 3 = 6
The sum of the first three prime numbers that end with a 9 (19,29,59) is 107
3.14
The sum of the first five prime numbers is 28. The sum of the cubes of the first three prime numbers is 160. The average of 28 and 160 is 94.