The interior angles of a 20 sided polygon add up to 3240 degrees
Icosagon is the TWENTY-sided Polygon ...... The sum of its interior angles = 3240 degrees
To find the sum of interior angles for any N-sided polygon = N*180° - 360°Solve the equation: N*180° - 360° = 3240°, for N, and N = 20, so a 20 sided polygon will have sum of interior angles = 3240°, and if it is a regular polygon, then each angle = 162°
The sum of the interior angles of a regular polygon can be calculated using the formula (n-2) * 180, where n is the number of sides. For a regular 20-sided polygon, the sum of the interior angles would be (20-2) * 180 = 3240 degrees.
An icosagon is a 20 sided polygon and its interior angles add up to 3240 degrees
n = (3240 + 360)/180 ie 20
20 sides
The interior angles of a 20 sided polygon add up to 3240 degrees
18 Angles on a straight line = 180 degrees interior angles 2880 + exterior angles 360 = 3240 degrees 3240 divided by 180 = 18 sides Note that the exterior sum of angles of any polygon is always 360 degrees.
The sum of the interior angles of a polygon with n sides is (n-2)*180 degrees So (n-2)*180 = 3240 Hence n-2 = 18 so that n = 20.
The interior angles of a 20 sided polygon add up to 3240 degrees
The interior angles add up to 3240 degrees
Icosagon is the TWENTY-sided Polygon ...... The sum of its interior angles = 3240 degrees
To find the sum of interior angles for any N-sided polygon = N*180° - 360°Solve the equation: N*180° - 360° = 3240°, for N, and N = 20, so a 20 sided polygon will have sum of interior angles = 3240°, and if it is a regular polygon, then each angle = 162°
There are 20 interior angles and they add up to 3240 degrees
The interior angles add up to 3240 degrees
Sum of the interior angles of a n-gon = (n-2)*180 degrees. So, for a polygon with 20 sides, the sum og the 20 interior angles is (20-2)*180 = 18*180 = 3240 degrees. Since it is a regular polygon, all interior angles are equal, and each one is 3240/20 degrees = 162 degrees.