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What is the sum of the interior angles of a regular 20-sided polygon?
The interior angles of an x-sided polygon would be: (x - 2) * 180. (20 - 2) * 180 = 3,240
What are the interior angles of a 20 sided polygon?
If the 20-sided polygon is a regular polygon, then:The sum of all 20 angles = (20 - 2)180⁰ = 18(180⁰) = 3240⁰Each angle measure = 3240⁰/20 = 162⁰
What is the sum of the measures in degrees of the interior angles of a 20 sided poylgon?
The sum of the interior angles in a n-sided polygon is (n-2) x 180o. For a 20 sided polygon: sum_interior_angles = (20 - 2) x 180o = 18 x 180o = 3240o.
What is the sum of interior angles icosagon?
3240o. The sum of the interior angles of a n sided polygon is sum = (n - 2) x 180o An icosagon has 20 sides, thus the sum of its interior angles is: sum = (20 - 2) x 180o = 3240o
What is the polygon that the sum of the measures of the interior angles is 3240 degrees?
To find the sum of interior angles for any N-sided polygon = N*180° - 360°Solve the equation: N*180° - 360° = 3240°, for N, and N = 20, so a 20 sided polygon will have sum of interior angles = 3240°, and if it is a regular polygon, then each angle = 162°
