Q: Interior angles of a 20 sided polygon?

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The name of a 20 sided polygon is Icosagon.

3240

I believe it may be a 20-sided polygon (a 20-gon). Usually the interior and exterior angles add up to 180. 180 - 162 = 18 So 18 is the exterior angle. Since the exterior angles add up to 360 degrees 360/18 = 20 There you have your answer.

The sum of the exterior angles of any polygon and the extension of its adjacent side is 360 degrees.If the 20 sided polygon is regular, then each angle is equal so that each one is 360/20 = 18 degrees.

Sum of the interior angles of a n-gon = (n-2)*180 degrees. So, for a polygon with 20 sides, the sum og the 20 interior angles is (20-2)*180 = 18*180 = 3240 degrees. Since it is a regular polygon, all interior angles are equal, and each one is 3240/20 degrees = 162 degrees.

Related questions

The interior angles of a 20 sided polygon add up to 3240 degrees

The interior angles of an x-sided polygon would be: (x - 2) * 180. (20 - 2) * 180 = 3,240

The interior angles of a 20 sided polygon add up to 3240 degrees

Sum of interior angles of n-sided polygon = 180n - 360 degrees. When n = 20 this gives 3240o

There are 20 interior angles and they add up to 3240 degrees

The interior angles add up to 3240 degrees

It is a regular 20 sided polygon

3240o

The sum of the interior angles in a n-sided polygon is (n-2) x 180o. For a 20 sided polygon: sum_interior_angles = (20 - 2) x 180o = 18 x 180o = 3240o.

If the 20-sided polygon is a regular polygon, then:The sum of all 20 angles = (20 - 2)180⁰ = 18(180⁰) = 3240⁰Each angle measure = 3240⁰/20 = 162⁰

3600 Degrees

3240o. The sum of the interior angles of a n sided polygon is sum = (n - 2) x 180o An icosagon has 20 sides, thus the sum of its interior angles is: sum = (20 - 2) x 180o = 3240o