2 x 5 x 5 = 50
As a product of its prime factors in exponents: 23*52 = 200
Just multiply one pair of your numbers to give you a product, and then multiply their product by your third number.
yes you can multiply 3 by 77 will give you 385 happy now?
1 x 31 31 is a prime number.
2 * 7 * 7 * 13 = 1274
As a product of its prime factors in exponents: 23*52 = 200
1 and 211. 211 is prime.
Just multiply one pair of your numbers to give you a product, and then multiply their product by your third number.
yes you can multiply 3 by 77 will give you 385 happy now?
This question is based on a misunderstanding. Most cryptography is based on numbers that are products of two very large prime numbers. Being the product of two primes means that these numbers are composite - not prime!
To find numbers that multiply to give you 231, you can factorize 231 and look for its prime factors. 231 = 3 * 7 * 11 So, the numbers you can multiply to get 231 are 3, 7, and 11.
1 x 31 31 is a prime number.
2 * 7 * 7 * 13 = 1274
It multiplies the numbers that are given to it. So to multiply 10 by 5 you could use the PRODUCT function to do it, like this: =PRODUCT(10,5) will give 50. =PRODUCT(3,4) will give 12. The Product function multiplies all the numbers in it to give a result. For example: =PRODUCT(5,10,3) will give 150. You can have up to 255 different values in a PRODUCT function, all of which will be multiplied. If you had numbers in every cell from A2 to A12 you could multiply them all in the following way: =PRODUCT(A2:A12)
Take the denominators and factor them into prime numbers. The LCM is the product of the prime numbers that were used the most. Here is an example. 1/30 and 1/24 30=2x3x5 24=2x2x2x3 LCM=2x2x2x3x5=120 Use that as the common denominator and multiply the numerator by the amount needed to multiply the denominator by to get the LCM.
If you take all the common prime factors between numbers and multiply them it will give you the gcf.
As a product of its prime factors: 2*3*3*3 = 54