77.45%
Assuming a normal distribution, the proportion falling between the mean (of 8) and 7 with standard deviation 2 is: z = (7 - 8) / 2 = -0.5 → 0.1915 (from normal distribution tables) → less than 7 is 0.5 - 0.1915 = 0.3085 = 0.3085 x 100 % = 30.85 % (Note: the 0.5 in the second sum is because half (0.5) of a normal distribution is less than the mean, not because 7 is half a standard deviation away from the mean, and the tables give the proportion of the normal distribution between the mean and the number of standard deviations from the mean.)
A standard normal distribution has a mean of zero and a standard deviation of 1. A normal distribution can have any real number as a mean and the standard deviation must be greater than zero.
In a normal distribution, approximately 68% of the data falls within one standard deviation of the mean. This means that around 34% of the data lies between the mean and one standard deviation above it, while another 34% lies between the mean and one standard deviation below it.
You need to know the standard deviation or standard error to answer the question.
34.1% with the normal distribution.
Assuming a normal distribution, the proportion falling between the mean (of 8) and 7 with standard deviation 2 is: z = (7 - 8) / 2 = -0.5 → 0.1915 (from normal distribution tables) → less than 7 is 0.5 - 0.1915 = 0.3085 = 0.3085 x 100 % = 30.85 % (Note: the 0.5 in the second sum is because half (0.5) of a normal distribution is less than the mean, not because 7 is half a standard deviation away from the mean, and the tables give the proportion of the normal distribution between the mean and the number of standard deviations from the mean.)
A standard normal distribution has a mean of zero and a standard deviation of 1. A normal distribution can have any real number as a mean and the standard deviation must be greater than zero.
In a normal distribution, approximately 68% of the data falls within one standard deviation of the mean. This means that around 34% of the data lies between the mean and one standard deviation above it, while another 34% lies between the mean and one standard deviation below it.
You need to know the standard deviation or standard error to answer the question.
34.1% with the normal distribution.
It the upper bound of the range is U, thenZL = (10.25 - 10.75)/0.8 = -0.625 and ZU = (U - 10.75)/0.8 Then the relevant proportion can be determined as the integral of the standard normal distribution between ZL and ZU.
The mean deviation (also called the mean absolute deviation) is the mean of the absolute deviations of a set of data about the data's mean. The standard deviation sigma of a probability distribution is defined as the square root of the variance sigma^2,
the t distributions take into account the variability of the sample standard deviations. I think that it is now common to use the t distribution when the population standard deviation is unknown, regardless of the sample size.
Standard deviation doesn't have to be between 0 and 1.
Standard deviation is the square root of the variance.
If the mean score is 100 and the standard deviation is 15, the distribution of scores is likely to follow a normal distribution, also known as a bell curve. In this distribution, approximately 68% of scores fall within one standard deviation of the mean (between 85 and 115), about 95% fall within two standard deviations (between 70 and 130), and about 99.7% fall within three standard deviations (between 55 and 145). This pattern indicates that most scores cluster around the mean, with fewer scores appearing as you move away from the center.
The answer will depend on the distribution of the variable.