what quadrant is (0,-15) in
I assume you mean (8, 0). If one or both of the coordinates are zero, the point is not in any of the four quadrants. Instead, it is on the axes - between two quadrants.
It is in quadrant IV.
8
y=0 is a horizontal line on the x-axis. Therefore, it does not lie in any quadrant.
(0-5) lies in First Quadrant
what quadrant is (0,-15) in
I assume you mean (8, 0). If one or both of the coordinates are zero, the point is not in any of the four quadrants. Instead, it is on the axes - between two quadrants.
The point (8,0) is on an axis (abscissa axis or x-axis) and is therefore not in a quadrant.
It is in quadrant IV.
The coordinate or Cartesian plane is divided into four quadrants by the axes. The axes, themselves, do not belong to any quadrant. Assuming the normal x and y-axes, Quadrant I : x > 0, y > 0 Quadrant II : X < 0, y > 0 Quadrant III : X < 0, y < 0 Quadrant IV: X > 0, y < 0 That's it. No special sides, nothing to solve.
8
(0, -3) is not in any quadrant. I lies on the border between two quadrants. Because zero is not positive or negative, it cannot be defined as in a quadrant
y=0 is a horizontal line on the x-axis. Therefore, it does not lie in any quadrant.
Points on the x-axis or y-axis are not in any quadrant. Therefore, (-3,0) is not contained in a quadrant.
If the signs of the Cartesian coordinates are: (+, +) => first quadrant (-, +) => second quadrant (-, -) => third quadrant (+, -) => fourth quadrant. If one of the coordinates is 0 then the point is on an axis and NOT in a quadrant. If both coordinates are 0 then the point is at the origin. If the location of the point is given in polar coordinates, then you only need the angle. Suppose the principal angle is Φ, then 0 < Φ < 90 degrees => first quadrant 90 < Φ < 180 => second quadrant 180 < Φ < 270 => third quadrant 270 < Φ < 360 => fourth quadrant. Again, if the angle is 90, 180 etc degrees, the point is on an axis. If the magnitude is 0 then the point is at the origin.
Origin