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Q: What r all the prime factors of 56?
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What number is A Main prime factor of 73?

The term "main prime factor" is interpreted as "prime factor" (all prime factors are main prime factors).Since 73 is prime, your question can be generalized to:What are the prime factors of a prime?You may know that all numbers have a unique factorization in primes. This is a theorem. What you need is the definition of a prime number to prove this theorem in the first place.A number which has only two divisors, namely 1 and the number itself, is called prime. Hence, by definition, the prime factors of a prime are the prime and 1.So your question is trivial, asking to recognize 73 to be a prime. The answer is 73.The question of how to determine that 73 is prime is a good one.Basically you can prove it by noting that it can not be divided by any prime smaller than 73^(1/2) < 8:73 / 2 = 36 R 1 -- the expression n R m means n with remainder m73 / 3 = 24 R 173 / 5 = 14 R 373 / 7 = 10 R 3Hence (since 2, 3, 5 and 7 are all primes smaller than 8), 73 is prime.2 is prime (there is not integer between 1 and 2)3 is prime, since 3/2 = 1 R 15 is prime, since 5/2 = 2 R 1 (we do not need to test with 3, because 5 < 3^2)7 is prime, since 7/2 = 3 R 1 (we do not need to test with 3, because 7 < 3^2)


What are all the factors of 110 demonstrate?

The prime factorisation of 110 is 2*5*11.Therefore all factors of 110 are 2p*5q*11r where each of p, q and r can be 0 or 1.


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Prime factorizations are expressions of numbers as products of prime factors. The prime factorization of 30 is 2 x 3 x 5.


How can you demonstrate finding all the factors of 110?

The prime factorisation of 110 is 2*5*11.Therefore all factors of 110 are 2p*5q*11r where each of p, q and r can be 0 or 1.


Definition of elementary set concepts in maths?

prove that the following two sets are equal A=set of prime factors of 36 B=set of prime factors of 108 r