63
100 - 7r = 44 Subtract 100 from both sides: -7r = -56 Divide both sides by -7: r = 8
if the x in the formula means multiply (next time please use * to denote multiplication) then: 7r-38
To solve the equation (100 \cdot 7r = 44), first divide both sides by 100, yielding (7r = \frac{44}{100}). Simplifying the right side gives (7r = 0.44). Finally, divide both sides by 7 to find (r = \frac{0.44}{7}), which equals approximately (0.062857). Thus, (r \approx 0.0629).
7r = 3r - 527r (- 3r) = 3r - 52 (- 3r)4r = - 524r / 4 = -52 / 4r = -13
No, 7r and 2 are not like terms. Like terms have the same variable raised to the same power, which means they must have identical variable components. In this case, 7r contains the variable "r," while 2 is a constant without any variable.
7 × (r + 8) = 7(r + 8) = 7r + 56
100 - 7r = 44 Subtract 100 from both sides: -7r = -56 Divide both sides by -7: r = 8
7r-43 = -36
how do i solve -3r+3r=-6(7+7r)-7(4-7r)
12 + 8r - 6 = 7r - 5 - 3 8r +6 = 7r -8 r = -14
I think so.r2 + 7r + 6 = [ (r+6) (r+1) ]
7r = r + r + r + r + r + r + r or r7
2r + 7r - 6t - r + 7t = 8r + t
If that's the equation 6r + 7 = 13 + 7r, r = -6
if the x in the formula means multiply (next time please use * to denote multiplication) then: 7r-38
To solve the equation (100 \cdot 7r = 44), first divide both sides by 100, yielding (7r = \frac{44}{100}). Simplifying the right side gives (7r = 0.44). Finally, divide both sides by 7 to find (r = \frac{0.44}{7}), which equals approximately (0.062857). Thus, (r \approx 0.0629).
7r = 3r - 527r (- 3r) = 3r - 52 (- 3r)4r = - 524r / 4 = -52 / 4r = -13