Since the area of a circle is S=πr2 and we intend to double the radius(2r) then the area of the new circle will be S'=π*(2r)2=4*πr2, an area 4 times greater than the initial one S'=4S.
Area = pi*40002 = 50265482.46 square feet
First off, let's clear up area and volume. Area is for two dimensional shapes, like squares and circles. Volume is for three dimensional shapes like cubes and spheres. The area of a cone would be the area of the ellipse at the base of the cone (the circle) plus the area of the pointy bit, when it's unrolled. This would be like the area you would need to paint if you painted the outside. Assuming that the base of the cone is a circle, then the area of the base is: pi * radius * radius (pies are square) The area of the pointy bit is: pi * radius * S, where S is the length of the slope from a point on to the circle to the tip (hypotenuse). Add the two together to get the total area = ( pi * r * S ) + ( pi * r * r ) Now the S length is really derived from the height of the cone (from the center of the circle to the point) and radius of the base circle. Remember Pythagoras, S = square root of ( ( h * h ) + ( r * r ) ) Well, if you are actually looking for the volume (how much water it takes to fill up the cone), then you need: volume = 1/3 * pi * radius * radius * height
It is the radius of the circle
Circumference = 2 * pi * s
The area of Circle S can be found by using the area formula for circles. The area of a circle is pi times the radius squared. So, the area of Circle S with a 1 inch radius is Pi inches squared.
S = (pi) * (radius)2
The formula for the area of a circle is πr2, or pi x radius^2 The radius of a circle is the diameter divided by two, and pi is approx. 3.1415926535
Since the area of a circle is S=πr2 and we intend to double the radius(2r) then the area of the new circle will be S'=π*(2r)2=4*πr2, an area 4 times greater than the initial one S'=4S.
Given: a square with side = s and a circle with radius = s (radius is equal to the length of the side of the square) Areasquare = side squared = s2 Areacircle = pi times the square of the radius = pi times s2 Areasquare : areacircle = s2 : pi s2 = 1 : pi (The ratio is one to pi.)
Area = pi*40002 = 50265482.46 square feet
First off, let's clear up area and volume. Area is for two dimensional shapes, like squares and circles. Volume is for three dimensional shapes like cubes and spheres. The area of a cone would be the area of the ellipse at the base of the cone (the circle) plus the area of the pointy bit, when it's unrolled. This would be like the area you would need to paint if you painted the outside. Assuming that the base of the cone is a circle, then the area of the base is: pi * radius * radius (pies are square) The area of the pointy bit is: pi * radius * S, where S is the length of the slope from a point on to the circle to the tip (hypotenuse). Add the two together to get the total area = ( pi * r * S ) + ( pi * r * r ) Now the S length is really derived from the height of the cone (from the center of the circle to the point) and radius of the base circle. Remember Pythagoras, S = square root of ( ( h * h ) + ( r * r ) ) Well, if you are actually looking for the volume (how much water it takes to fill up the cone), then you need: volume = 1/3 * pi * radius * radius * height
It is the radius of the circle
Circumference = 2 * pi * s
If you draw a line from the center of a circle to the edge of a circle, you have drawn the radius of the circle. If you draw a line from the edge of a circle through the center of the circle and on to the edge on the opposite side, you have drawn the diameter of a circle. The radius of a circle is one half the diameter of a circle.
The area of a circle if the diameter was s 7ft is 38.48ft
Area = πSr + πr² Where: S = the slant length of the cone r = radius of the base πr² = area of the base of the cone πSr = area of outside of cone -------------------------------------------------------------- The surface area of the cone is the sum of the area of the base and the slanted surface. The area of the base is the area of a circle = πr² The area of the slanted surface can be calculated by realising that if the slanted surface is cut by a straight line from the apex to the base it can be "unrolled" into a sector of a circle. Thus it is a fraction of the area of a circle. The length of the circumference of the sector is the length of the circumference of the base of the cone; the length of the whole circle from which this is a sector is the circle with radius of the slant height of the cone; thus: area slanted surface = πS² × ((2πr)/(2πS)) = πSr Thus the surface area of a cone = area base + area slant surface → surface_area_cone = πr² + πSr = πr(r + S) where r is the radius of the base and S is the slant height.