45 sequences. Make it easier and think what are the 2 tail flips. They are: 1-2; 1-3;1-4...1-10. That is 9 sequences starting with 1. There are 9 sequences starting with 2, 9 starting with 3, etc, up to 10. That makes 90 sequences, but since 1-2 is the same as 2-1, ie order doesn't matter, divide that in half to get 45.
There are infinitely many arithmetic sequences, and infinitely many geometric sequences, and polynomials, and power equations. Basically, there are too many possible sequences. Arithmetic ones, for example: 13, 14, 15, 16, 17 9, 11, 13, 15, 17 5, 8, 11, 14, 17 1, 5, 9, 13, 17 -3, 2, 7, 12, 17 I hope you get the idea. These are all increasing, and the common differences are integers but both these conditions can be changed.
sum(1/(n^2+1))
0.5n(n+1)
It is not possible to give an accurate answer to this question because not all number are used and those that are, are not issued randomly. For example, some sequences are reserved for the start of mobile or cell phone numbers, other sequences for toll free or premium rate numbers. But, if you assume that all numbers are equally likely to be used, then the answer is (1/10)*(1/10) = 1/100
The Fine Structures are as follows: 1) The Start Codon: Met is specific for one amino acid [Met] yet f-Met uniquely specifies the Start codon.2) There are two kinds of 'upstream promotion' sequences: i) the furthest upstream are called the 'Enhancer sequences', and ii) the control sequences nearer to the Gene are called the 'Promoter sequences'.3) Right beside the Promoter sequence is always found the Operator Sequence: this proffers the attachment for and to the Start Codon. After the Start Codon, the Protein Coding Sequence ensues, followed by Termination sequences.
No, but it can be expressed as the sum of two geometric sequences. F_n = a^n + b^n a = (1+sqrt{5})/2 b = (1-sqrt{5})/2
45 sequences. Make it easier and think what are the 2 tail flips. They are: 1-2; 1-3;1-4...1-10. That is 9 sequences starting with 1. There are 9 sequences starting with 2, 9 starting with 3, etc, up to 10. That makes 90 sequences, but since 1-2 is the same as 2-1, ie order doesn't matter, divide that in half to get 45.
There would be a possibility of about 16 sequences.
1. Start with any two numbers . ( Use 0 and 1 to get the standard sequence) 2. 0 1 Rule: Add each pair of numbers to get the next term 0 1 1 ( add 0 + 1 to get 1) 0 1 1 2 ( add 1 + 1 to get 2) 0 1 1 2 3 (1+2 = 3) 0 1 1 2 3 5 (2 + 3 = 5) 0 1 1 2 3 5 8 and so on forever.
Geeking Out On--- - 2012 Title Sequences 1-12 was released on: USA: 27 September 2012
There are infinitely many arithmetic sequences, and infinitely many geometric sequences, and polynomials, and power equations. Basically, there are too many possible sequences. Arithmetic ones, for example: 13, 14, 15, 16, 17 9, 11, 13, 15, 17 5, 8, 11, 14, 17 1, 5, 9, 13, 17 -3, 2, 7, 12, 17 I hope you get the idea. These are all increasing, and the common differences are integers but both these conditions can be changed.
sum(1/(n^2+1))
5 books can be lined up on a shelf in (5 x 4 x 3 x 2 x 1) = 120 different sequences.
start and stop sequences Also called Star and Stop codons. These are base triplets in the DNA base sequence. Examples of Stop Codons ar TAG or TGA.
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Start by rewriting as 1 and 6/10 which is........ 1 and 3/5 then 5 * 1 + 3 = 8/5