If ( pq ) and ( qr ) are both true statements, then it follows that both ( p ) and ( q ) must be true (since ( pq ) is true) and both ( q ) and ( r ) must be true (since ( qr ) is true). Consequently, this implies that ( q ) is true in both cases. However, we cannot definitively conclude the truth values of ( p ) or ( r ) without additional information. Thus, the statements themselves do not inherently guarantee the truth of ( p ) or ( r ) alone.
Since rs is the perpendicular bisector of pq, it follows that point s is the midpoint of segment pq, meaning that ps is equal to qs. Additionally, because rs is perpendicular to pq, the angles formed at the intersection (∠prs and ∠qrs) are both right angles (90 degrees). Consequently, any point on line rs is equidistant from points p and q.
2 + pq
6
False. In order for the line PQ to lie in plane B, then both P and Q must lie in plane B.
It means "premium quality". It is not an official form of grading.
QPR is congruent to SPR PR is perpendicular to QPS PQ =~ QR PT =~ RT
T is the midpoint of PQangle PTR = 90 degreesRS _l_ PQPT = QT
2 + pq
6
Is PQ |_ RS
z=pq
3
p(q + r) = pq + pr is an example of the distributive property.
PQ ST
If you are working with real numbers, or even complex numbers, pq is the same as qp, so the result is the same as 2pq. If you use some multiplication that is NOT commutative (such as, when you multiply matrices), you can't simplify the expression.
False. In order for the line PQ to lie in plane B, then both P and Q must lie in plane B.
It means "premium quality". It is not an official form of grading.