Chat with our AI personalities
Let a be the number of ounces of 25% alcohol required. Then, 25a + (30x9) = 28(9 + a) 25a + 270 = 252 + 28a 3a = 18 a = 6 Then 6 ounces of 25% alcohol + 9 ounces of 30% alcohol produces 15 ounces of 28% alcohol.
684 ml
210Type your answer here...
There are 3 litres of alcohol in your starting mixture of 4 litres. If you add 6 litres of water you will have 3 litres of alcohol in a total of 10 litres. This is the required strength.
x = volume of 95% y = volume of 30% so (x+y) is volume of 70% 0.95 x + 0.30 y = 0.70(x+y) 0.95 x + 0.30 y = 0.70x + 0.70y 0.25x = 0.40y x/y = 0.40/0.25 = 8/5 for every 8 volumes of 95% mix in 5 volumes of 30%the volumes can be ml, liters, cups, pints etc.