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Pharmacist mixed a 20 percent solution with a 30 percent solution to obtain 100 liters of a 24 percent solution How much of the 20 percent solution did the pharmacist use in the mixture?
10
A solution containing 30 percent insecticide is to be mixed with a solution containing 50 percent insecticide to make 200 L of a solution containing 42 percent insecticide How much of the 30 percent i?
80 liters
A chemist has one solution that is 60 percent chlorinated and another that is 40 percent chlorinated How much of each solution is needed to make a 100 liter solution that is 50 percent chlorinated?
50 Liters of the 60% solution.
How much water should be added to four liters of 75 percent alcohol to make a mixture of 30 percent alcohol?
There are 3 litres of alcohol in your starting mixture of 4 litres. If you add 6 litres of water you will have 3 litres of alcohol in a total of 10 litres. This is the required strength.
How much pure alcohol must be added to 7 liters of 10 percent alcohol solution to increase the concentration to 30 percent alcohol?
2 litersLet X represent the amount of pure alcohol to be added to the 7 liters of 10% alcohol solution to get a 30% alcohol solution. We want .3(7+x)=.1*7+x [because we need the alcohol in the final solution to equal the amount of alcohol in the original solution plus the amount of alcohol we are adding). Solving for x, we get:.3(7+x)=.1*7+x2.1+.3x=.7+x1.4=.7x2=xThus, 2 liters of pure alcohol needs to be added to the solution.Added noteto deal with the so called 'dilution contraction' of total volumeIf it were % by MASS ( %m/m), it's quite easy to do (based on the 'Mass Conservation Law). You calculate with mass (kg) and mass-% (%m/m) i.s.o. volume (L) and vol% (%v/v).However if the meaning was: % by Volume ( %v/v) then calculation appears to become quite complicated, but not impossible if you know at least the density values of all solutions (original 100%v/v or 10%v/v and final 30%v/v).DO NOT use: (orig. volume) + (added volume) = final volume, as done above, if exact figures are necessary.It's only a rule of thump, an approximation. This is because fluids can contract on mixing at dilution. There is no rule such as: conservation of volume.Your case: 7 L + 2 L (is not equal but) < 9 L final solution.
A pharmacist mixed a 20 percent solution with a 30 percent solution to obtain 100 liters of a 24 percent solution How much of the 20 percent solution did the pharmacist use in the mixture?
A pharmacist mixed a 20 percent solution with a 30 percent solution to obtain 100 liters of a 24 percent solution. How much of the 20 percent solution did the pharmacist use in the mixture (in liters).
Pharmacist mixed a 20 percent solution with a 30 percent solution to obtain 100 liters of a 24 percent solution How much of the 20 percent solution did the pharmacist use in the mixture?
10
A chemist is making 200 L of a solution that is 62 percent acid He is mixing an 80 percent acid solution with a 30 percent acid solution How much of the 80 percent acid solution will he use?
The chemist will use 100 liters of the 80% acid solution and 100 liters of the 30% acid solution to make a 200-liter solution that is 62% acid. The amount of acid in the 80% solution will be 0.8 * 100 = 80 liters, and in the 30% solution, it will be 0.3 * 100 = 30 liters.
Jerry is experimenting with chemicals in the laboratory He mixes a solution that is 10 percent acid with a solution that is 30 percent acid How much of the 10 percent acid solution will be needed to m?
10 liters
A solution containing 30 percent insecticide is to be mixed with a solution containing 50 percent insecticide to make 200 L of a solution containing 42 percent insecticide How much of the 30 percent i?
80 liters
A chemist has one solution that is 60 percent chlorinated and another that is 40 percent chlorinated How much of each solution is needed to make a 100 liter solution that is 50 percent chlorinated?
50 Liters of the 60% solution.
How much water must be added to 12 L of a 40 percent solution of alcohol to obtain a 30 percent solution?
4 litres
Mary is experimenting with chemicals in the laboratory She mixes a solution that is 10 percent acid with a solution that is 25 percent acid How much of the 10 percent acid solution will be needed to m?
16 2/3 liters
How much 95 percent alcohol is required to prepare 5 L of 70 percent alcohol?
70/19 or 3.684 liters. Here's how. 5 liters of 70% alcohol contains 3.5 liters of pure alcohol. So if X equals the answer to the question, then 0.95 * X = 3.5. That means X = 3.5/0.95 or "normalizing" the fraction gives 70/19 = 3.684L.
A solution is 10 percent ethanol if you have 6L of solution how much ethanol is is the solution?
6 liters of a solution that is 10% ethanol contains 0.6 liters of ethanol.
How much alcohol can you bring from US to Brazil?
10 liters of alcohol (above 22% alcohol) or 110 liters of bee
A chemist has one solution which is 50 percent acid and a second solution which is 25 percent acid how much of each should be mixed to make a 10 liters of a 40 percent acid solution?
6 litres of 50% + 4 litres of 25%
