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It is: 0 because 205 = 0

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Q: What the product of 2 x 0 x5?
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How do you solve x - x x?

x10 = x5.x5 = (x5)2 [x power five whole squared] Equation is x10 + x5 - 2 Replacing x10 (x5)2+x5 - 2 Substituting x5 by Y Equation becomes Y2 + Y - 2 = 0 Y2 + 2Y - Y - 2 = 0 Y(Y + 2) - 1(Y+2) = 0 (Y-1)(Y+2) = 0 The values of Y are 1 and -2 Y = x5 = 1 Therefore, x = 1 Y = x5 = -2 x = fifth root of -2, which is an imaginary value.


If The product of x and negative 4 is 8 more than 2 added to negative 5 times that number what equation could be used to solve for x?

x*-4=8+(2-5*x) =-4x=8+2-x5 x*-4=8+(2-5*x) =-4x=8+2-x5 x*-4=8+(2-5*x) =-4x=8+2-x5


What is X to the 0 power over x to the -5 power?

5


What are the real roots of x5 - 2x4 - 24x3 equals 0?

x5 - 2x4 - 24x3 = 0 x3(x2 - 2x - 24) = 0 x3(x2 + 4x - 6x - 24) = 0 x3(x - 6)(x + 4) = 0 x = {-4, 0, 6}


What is the product of the roots of the equation 2xsquare-x-2 equals 0?

The product of the roots of the equation 2x2 -x -2 = 2 is 2x2 -x -2 = 2.


How do you round to estimate the product 38 x 2?

To round to estimate the product of 38 x 2, you first round each number to a more manageable value. In this case, you can round 38 to 40 and 2 to 0. Then, multiply the rounded numbers together to get an estimate of the product. In this case, 40 x 0 = 0. So, the estimated product of 38 x 2 is 0.


What is 6x squared plus 4x equals 0?

6x^2+4x=0 Divide everything by two 3x^2+2x=0 factor out an x x(3x+2)=0 Zero Product Property states that you can break apart the product when it is equal to zero because for this to occur either one or both of the factors must equal 0. x=0 or 3x+2=0 3x=-2 x=-2/3


Why are there two solutions to quadratic equations?

In theory, a quadratic equation can be separated into two factors. For example, in the equation x2 - 5x + 6 = 0, the left part can be factored as (x-3)(x-2) = 0. For the product to be zero, any of the two factors must be zero, so if either x - 3 = 0, or x - 2 = 0, the product is also zero. This gives you the two solutions.In theory, a quadratic equation can be separated into two factors. For example, in the equation x2 - 5x + 6 = 0, the left part can be factored as (x-3)(x-2) = 0. For the product to be zero, any of the two factors must be zero, so if either x - 3 = 0, or x - 2 = 0, the product is also zero. This gives you the two solutions.In theory, a quadratic equation can be separated into two factors. For example, in the equation x2 - 5x + 6 = 0, the left part can be factored as (x-3)(x-2) = 0. For the product to be zero, any of the two factors must be zero, so if either x - 3 = 0, or x - 2 = 0, the product is also zero. This gives you the two solutions.In theory, a quadratic equation can be separated into two factors. For example, in the equation x2 - 5x + 6 = 0, the left part can be factored as (x-3)(x-2) = 0. For the product to be zero, any of the two factors must be zero, so if either x - 3 = 0, or x - 2 = 0, the product is also zero. This gives you the two solutions.


What is x cubed divided by square root of x?

x3/x1/2 = x5/2.


What is the product of 7 and 0?

Product = Multiply7 x 0 = 0


What is the product of the 2 solutions of the equation x'2 4'x-21 equals 0?

3 x - 7 = -21


What is 3 to the power of x minus 2 times 3 to the power of x minus 2?

x5