1: 2.34
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Let the diagonals be x and (x+1):- If: 0.5*x*(x+1) = 66 Then: x^2 +x = 132 Or: x^2 +x -132 = 0 Factorizing the above: (x+12)(x-11) = 0 meaning x = -12 or x = 11 Therefore the diagonals are: 11 cm and 12 cm in lengths Check: 0.5*11*(11+1) = 66 square cm
1/3 x 32 x pi x 11 = 103.67cm3
2.54 cm = 1 inch 11 in x 2.54 cm/in = 27.94 cm = 279.4 mm
330 cm3 Volume = area_of_end x length = (1/2 x 12 cm x 5 cm) x 11 cm = 330 cm3
5.6471