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What are the lengths of the diagonals of a quadrilateral that has an area of 66 square cm when one of the diagonals is 1 cm greater than the other and they intersect at right angles?
Wiki User
∙ 6y ago
Let the diagonals be x and (x+1):-
If: 0.5*x*(x+1) = 66
Then: x^2 +x = 132
Or: x^2 +x -132 = 0
Factorizing the above: (x+12)(x-11) = 0 meaning x = -12 or x = 11
Therefore the diagonals are: 11 cm and 12 cm in lengths
Check: 0.5*11*(11+1) = 66 square cm
Wiki User
∙ 6y ago
Wiki User
∙ 6y agoThey are 7.64 and 8.64 cm, respectively.
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