Let the diagonals be x and (x+1):-
If: 0.5*x*(x+1) = 66
Then: x^2 +x = 132
Or: x^2 +x -132 = 0
Factorizing the above: (x+12)(x-11) = 0 meaning x = -12 or x = 11
Therefore the diagonals are: 11 cm and 12 cm in lengths
Check: 0.5*11*(11+1) = 66 square cm
No because a kite is a 4 sided quadrilateral with two diagonals of different lengths that intersect each other at right angles.
The given vertices when plotted on the Cartesian plane forms a rectangle with diagonals of square root of 50 in lengths and they both intersect at (3.5, 4.5)
That will depend on the lengths of the diagonals of the rhombus which are of different lengths and intersect each other at right angles but knowing the lengths of the diagonals of the rhombus it is then possible to work out its perimeter and area.
No because the diagonals of a parallelogram are of different lengths
A parallelogram with sides whose lengths are half the diagonals of the original quadrilateral.
No because a kite is a 4 sided quadrilateral with two diagonals of different lengths that intersect each other at right angles.
The given vertices when plotted on the Cartesian plane forms a rectangle with diagonals of square root of 50 in lengths and they both intersect at (3.5, 4.5)
That will depend on the lengths of the diagonals of the rhombus which are of different lengths and intersect each other at right angles but knowing the lengths of the diagonals of the rhombus it is then possible to work out its perimeter and area.
No because the diagonals of a parallelogram are of different lengths
A parallelogram with sides whose lengths are half the diagonals of the original quadrilateral.
diagonals
A kite is a quadrilateral that is named thus because of it's kite-like appearance. It has two pairs of sides with equal lengths that are adjacent and congruent. The diagonals of a kite intersect at ninety degrees. See the 'related link' for a picture.
Let the lengths of the diagonals be x and (x+4) If: 0.5*x*(x+4) = 110.5 Then by transposing the terms: x^2 +4x -221 = 0 Factorizing the above: (x+17)(x-13) = 0 meaning x = -17 or x =13 Therefore the lengths of the diagonals are: 13cm and 17cm Check: 0.5*13*(13+4) = 110.5 square cm
A quadrilateral has four sides with lengths, two diagonals with lengths, four inside angles, four outside angles, and an area. The angles are the only things you can measure with a protractor.
I'm some cases yes while in others no :)
Using the cosine formula in trigonometry the diagonals of the quadrilateral works out as 5.71cm and 6.08cm both rounded to two decimal places
The lengths of the diagonals work out as 12 cm and 16 cm