The numbers are 69, 70 and 71.
14 x 15 = 210
The numbers are 14 and 15.
To find three numbers that add to 630 and can be represented using multiplication, consider the numbers 210, 210, and 210. While these three numbers add up to 630 (210 + 210 + 210 = 630), their product is (210 \times 210 \times 210). However, if you're looking for a multiplication factor, you could consider (1 \times 1 \times 630) or any variation thereof, where two of the numbers are 1 and the third is 630.
Middle integer must be one-third of the sum, in this case 70. Other two are therefore 68 and 72
121, 169, 289
5*6*7 = 210
The numbers are 69, 70, and 71.
14 x 15 = 210
They are 14 and 15.
The numbers are 14 and 15.
210 and 211
The numbers are 51, 52, 53 and 54.
You cannot.If you have any two consecutive numbers, one of them must be odd and the other even. So their sum must be odd and therefore cannot be 702 nor 210
Consecutive numbers can't both be multiples of 7. The LCM of consecutive numbers is their product. 14 and 15 are consecutive numbers whose LCM is a multiple of 7 that is greater than 200.
702 = 26 x 27; 210 = 14 x 15.
Here's how you can work it out: First, let "x" be the first of those three numbers. We know that those numbers are three consecutive even integers, which tells us that the other numbers are "x + 2" and "x + 4". We also know that the three of them added together give us 210, so we can say: x + (x + 2) + (x + 4) = 210 ∴ 3x + 6 = 210 ∴ 3x = 204 ∴ x = 68 We now know that the lowest number is 68, which tells us that the other two must be 70 and 72. To check that, we simply add them together: 68 + 70 + 72 = 210 which confirms our answer.
Middle integer must be one-third of the sum, in this case 70. Other two are therefore 68 and 72