5*6*7 = 210
The numbers are 69, 70, and 71.
69, 70, 71
You can solve this in two ways.1) Trial and error. That is, try multiplying two consecutive integers; if the product is too large, try smaller integers; if the product is too small, try larger consecutive integers. 2) Call the two consecutive integers "n" and "n+1", and solve the equation: n(n+1)=210
(x)(x + 1)(x + 2) = 210 (x^2 + x)(x + 2) = 210 x^3 + 2x^2 + x^2 + 2x = 210 x^3 + 3x^2 + 2x = 210 x^3 + 3x^2 + 2x - 210 = 0 Let's try 5, as a factor of 210. 5] 1 3 2 -210 5 40 -210 ---- 8 42 0 remainder, so 5 is a root. Since 5 is a root of the equation, let say that 5 is the first number. So, the second number is 6, and the third number is 7. Check: 5 x 6 x 7 = 210
(3/5*210)-(2/3*96) = 62
They are 14 and 15.
The numbers are 14 and 15.
The numbers are 69, 70, and 71.
The numbers are 69, 70 and 71.
702 = 26 x 27; 210 = 14 x 15.
69, 70, 71
Consecutive numbers can't both be multiples of 7. The LCM of consecutive numbers is their product. 14 and 15 are consecutive numbers whose LCM is a multiple of 7 that is greater than 200.
14 x 15 = 210
210 and 211
The numbers are 51, 52, 53 and 54.
The product of 5 x 6 x 7 is 210.
It is: 2*3*5*7 = 210