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Q: What three consecutive numbers have a product of 210?

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The numbers are 69, 70, and 71.

69, 70, 71

You can solve this in two ways.1) Trial and error. That is, try multiplying two consecutive integers; if the product is too large, try smaller integers; if the product is too small, try larger consecutive integers. 2) Call the two consecutive integers "n" and "n+1", and solve the equation: n(n+1)=210

(x)(x + 1)(x + 2) = 210 (x^2 + x)(x + 2) = 210 x^3 + 2x^2 + x^2 + 2x = 210 x^3 + 3x^2 + 2x = 210 x^3 + 3x^2 + 2x - 210 = 0 Let's try 5, as a factor of 210. 5] 1 3 2 -210 5 40 -210 ---- 8 42 0 remainder, so 5 is a root. Since 5 is a root of the equation, let say that 5 is the first number. So, the second number is 6, and the third number is 7. Check: 5 x 6 x 7 = 210

511 and 2100

Related questions

They are 14 and 15.

The numbers are 14 and 15.

The numbers are 69, 70, and 71.

The numbers are 69, 70 and 71.

69, 70, 71

702 = 26 x 27; 210 = 14 x 15.

14 x 15 = 210

210 and 211

Consecutive numbers wouldn't both be multiples of 7. If you mean consecutive multiples of 7, the LCM of 210 and 217 is 6510 which is their product divided by 7.

The numbers are 51, 52, 53 and 54.

The product of 5 x 6 x 7 is 210.

It is: 2*3*5*7 = 210

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