Q: What three consecutive numbers have a product of 210?

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The numbers are 69, 70, and 71.

69, 70, 71

You can solve this in two ways.1) Trial and error. That is, try multiplying two consecutive integers; if the product is too large, try smaller integers; if the product is too small, try larger consecutive integers. 2) Call the two consecutive integers "n" and "n+1", and solve the equation: n(n+1)=210

(x)(x + 1)(x + 2) = 210 (x^2 + x)(x + 2) = 210 x^3 + 2x^2 + x^2 + 2x = 210 x^3 + 3x^2 + 2x = 210 x^3 + 3x^2 + 2x - 210 = 0 Let's try 5, as a factor of 210. 5] 1 3 2 -210 5 40 -210 ---- 8 42 0 remainder, so 5 is a root. Since 5 is a root of the equation, let say that 5 is the first number. So, the second number is 6, and the third number is 7. Check: 5 x 6 x 7 = 210

511 and 2100

Related questions

They are 14 and 15.

The numbers are 14 and 15.

The numbers are 69, 70, and 71.

The numbers are 69, 70 and 71.

702 = 26 x 27; 210 = 14 x 15.

69, 70, 71

Consecutive numbers can't both be multiples of 7. The LCM of consecutive numbers is their product. 14 and 15 are consecutive numbers whose LCM is a multiple of 7 that is greater than 200.

14 x 15 = 210

210 and 211

The numbers are 51, 52, 53 and 54.

The product of 5 x 6 x 7 is 210.

You cannot.If you have any two consecutive numbers, one of them must be odd and the other even. So their sum must be odd and therefore cannot be 702 nor 210