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4m+15=8m-5 or,4m=20 or,m=5
4m
2(4m - 3)
There cannot be a 12m rectangle. A rectangle is a two dimensional object and so there must be two linear measures to describe it. Either there is measure of another length, for example a 12m x 8m rectangle. In that case the question is redundant. Or the 12m is intended as a measure of area and should actually have been 12 SQUARE metres. However, in that case, there are infinitely many possible solutions.
24
It appears to be a scalene triangle from the given dimensions.
m2 + 8m - 65 = (m + 13) (m - 5)
The two monomials with a greatest common factor of 4M would be 4M and another monomial that includes 4M as a factor. For example, 4M and 12M would have a greatest common factor of 4M. This is because both 4M and 12M can be divided by 4M without a remainder. The greatest common factor represents the largest monomial that can divide evenly into both monomials.
Well, honey, to find the perimeter of a rectangle, you add up all the sides. So, for your rectangle with sides of 12m and 8m, you simply add 12 + 12 + 8 + 8 to get a perimeter of 40 meters. Voila!
The area of rectangle is : 96.0
4m+15=8m-5 or,4m=20 or,m=5
A Kabaddi or Kabbadi Court measures 10m x 13m for men and 8m x 12m for women
To determine the number of triangles that can be formed with side lengths of 4m, 4m, and 7m, we can use the triangle inequality theorem. For a triangle to exist, the sum of the lengths of any two sides must be greater than the length of the third side. In this case, 4m + 4m = 8m, which is greater than 7m. Therefore, a triangle can be formed. Since all three sides are equal in length, this triangle is an equilateral triangle. So, there is only one triangle that can be formed with side lengths of 4m, 4m, and 7m.
It is 50%.
4m
96m3
2(4m - 3)