25 and 26
The numbers are 24 and 25.
Let x = first number x + 1 = next consecutive number x ( x + 1) = 600 X^2 + x -600 = 0 factor: (X-24) (x +25) = 0 X = 24 Answer: 24,25
600 ÷ 17 = 355/17 2000 ÷ 17 = 11711/17 → 117 - 35 = 82 integers between 600 and 2000 are divisible by 17.
10x60, 1x600
The sum of consecutive integers will always be odd. Consecutive odd numbers will be even. 299 + 301 = 600
25 and 26
The numbers are 24 and 25.
The numbers are 24 and 25.
24 and 25 or -25 and -24
Let x = first number x + 1 = next consecutive number x ( x + 1) = 600 X^2 + x -600 = 0 factor: (X-24) (x +25) = 0 X = 24 Answer: 24,25
The sum of the first 600 consecutive odd numbers is 360,000.
They are page numbers 24 and 25 . ( 24 x 25 = 600 ) The easiest way to solve this is by trial and error. Multiply two consecutive numbers; if the product is too low, try larger numbers, if it is too high, try smaller numbers. You can also write an equation and use the quadratic formula. The equation in this case is x(x+1) = 600. Re-written for use of the quadratic equation, it becomes x2 + x - 600 = 0. This will give you a positive and a negative solution; only the positive solution is sensible in this case.
They are consecutive odd numbers: 299 and 301.
Answer : 24 and 25 (24 x 25 = 600) Let the two numbers be represented by n and n + 1. n(n + 1) = 600 : n2 + n - 600 = 0 This equation can be factored (n + 25) (n - 24) = 0 As we only require the positive number solution then this occurs when n - 24 = 0, n = 24. As n = 24 then n + 1 = 25
600
24 and 25 are consecutive numbers that are factors of 600.