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25 and 26
The numbers are 24 and 25.
Let x = first number x + 1 = next consecutive number x ( x + 1) = 600 X^2 + x -600 = 0 factor: (X-24) (x +25) = 0 X = 24 Answer: 24,25
600 ÷ 17 = 355/17 2000 ÷ 17 = 11711/17 → 117 - 35 = 82 integers between 600 and 2000 are divisible by 17.
10x60, 1x600
The sum of consecutive integers will always be odd. Consecutive odd numbers will be even. 299 + 301 = 600
25 and 26
The numbers are 24 and 25.
The numbers are 24 and 25.
24 and 25 or -25 and -24
Let x = first number x + 1 = next consecutive number x ( x + 1) = 600 X^2 + x -600 = 0 factor: (X-24) (x +25) = 0 X = 24 Answer: 24,25
The sum of the first 600 consecutive odd numbers is 360,000.
They are consecutive odd numbers: 299 and 301.
Answer : 24 and 25 (24 x 25 = 600) Let the two numbers be represented by n and n + 1. n(n + 1) = 600 : n2 + n - 600 = 0 This equation can be factored (n + 25) (n - 24) = 0 As we only require the positive number solution then this occurs when n - 24 = 0, n = 24. As n = 24 then n + 1 = 25
600
24 and 25 are consecutive numbers that are factors of 600.
600 ÷ 17 = 355/17 2000 ÷ 17 = 11711/17 → 117 - 35 = 82 integers between 600 and 2000 are divisible by 17.