There are actually three answers to your question: 42 * 9, 54 * 7, and 63 * 6 all equal 378.
How about: 14*27 = 378 as one example
378
42 x 9 or 63 x 6
To find the number that is 378 times as big as 1756, you multiply the two numbers together: ( 378 \times 1756 = 663,888 ). Therefore, the number is 663,888.
The three digits that multiply together to equal 378 are 3, 7, and 18. However, if you're looking for three single-digit integers, the only combination is 3, 7, and 9, since (3 \times 7 \times 9 = 189), which does not equal 378. The prime factorization of 378 is (2 \times 3^3 \times 7), indicating that combinations of these factors can be used, but no set of three distinct single-digit integers will yield 378.
To find a two-digit number multiplied by a one-digit number to equal 378, we need to break down 378 into its prime factors: 2 x 3 x 3 x 3 x 7. The factors must be distributed between the two numbers. The closest combination is 18 x 21, which equals 378.
How about: 14*27 = 378 as one example
378
189
663,768
42 x 9 or 63 x 6
7
42 because... 9x = 378 x = 378/9 x = 42
To find the number that is 378 times as big as 1756, you multiply the two numbers together: ( 378 \times 1756 = 663,888 ). Therefore, the number is 663,888.
To determine how many times 9 can go into 378, you divide 378 by 9. The result is 42, meaning that 9 can go into 378 42 times without any remainder. This is because 42 multiplied by 9 equals 378.
The three digits that multiply together to equal 378 are 3, 7, and 18. However, if you're looking for three single-digit integers, the only combination is 3, 7, and 9, since (3 \times 7 \times 9 = 189), which does not equal 378. The prime factorization of 378 is (2 \times 3^3 \times 7), indicating that combinations of these factors can be used, but no set of three distinct single-digit integers will yield 378.
378 ÷ 42 = 9