13
The two digit numbers in which the tens digit is five greater than the units digit are:5061728394The number we are looking for is ten times the sum of its digits, and so must be a multiple of 10. The only one of the above numbers which fits this is 50, as 5 is five greater than 0, and 50 = 10 x (5+0).
The units digit of 159*445*7762*39 is the units digit of the product of the units digits of the four numbers, that is, the units digit of 9*5*2*9 Since there is a 5 and a 2 in that, the units digit is 0.
There are 5 of them.
There are infinitely many options. Two simple ones are:the addition of 0 and -5, andthe multiplication of 1 and -5.
5 and -5
How many numbers are 10 unitβs from 0 on the number line
-5 and +5.
Two numbers that equal 5 when adding are:0 + 5 or 5 + 0 1 + 4 or 4 + 1 3 + 2 or 2 + 3
13
0 Look at the product of the first 3 prime numbers: 2 x 3 x 5 = 30. Any number multiplied by 30 will have a 0 in the units digit. So, no matter how many prime numbers you are multiplying, if once you have a number ending in 0, all of the rest will end in 0.
The two digit numbers in which the tens digit is five greater than the units digit are:5061728394The number we are looking for is ten times the sum of its digits, and so must be a multiple of 10. The only one of the above numbers which fits this is 50, as 5 is five greater than 0, and 50 = 10 x (5+0).
a number that is halfway between 0 and 5 is 2.5.
0
The units digit of 159*445*7762*39 is the units digit of the product of the units digits of the four numbers, that is, the units digit of 9*5*2*9 Since there is a 5 and a 2 in that, the units digit is 0.
.13 is .13 units away from 0. To find how close it is to .032 we subtract..13-.032 is .098 so since this is less than .13 we can say that .13 is closer to .032 than it is to 0.It is hard to see this with these numbers. Let's use 3. Is it closer to 0 or 5. 3 is 3 units away from 0 and 5-3=2 so it is 2 units away from 5. In this case it is closer to 5.
If you start at 0 then: 0+5-3+4=6 I hope it helped you