There's only one number that's equal to 17. That number is 17.
There's only one number that's equal to 64. That number is 64.
Therefore, there's no number that's equal to both 17 and 64.
The sum of the prime numbers 11 and 53 equals 64.
61 and 3
They could be: 64 and 36 because 64+36 = 100 and 64-36 = 28
The numbers are 62 and 64 are two consecutive integers that equal 126.
1 & 64, 2 & 32, 4 & 16, or 8 & 8
The sum of the prime numbers 11 and 53 equals 64.
44
61 and 3
They could be: 64 and 36 because 64+36 = 100 and 64-36 = 28
The numbers are 62 and 64 are two consecutive integers that equal 126.
1 & 64, 2 & 32, 4 & 16, or 8 & 8
to factor (x2-16x+64), you need to find two number whose product is 64 and whose sum is 16. These two numbers are 8 and 8. (x2-16x+64)=(x-8)(x-8)
This problem actually has no solution. Any two numbers that will add to 6.5 will be too small to produce a multiple equal to 64. However, for problems like this in general, writing the question as a formula might help you solve it. 1. Assume the numbers are x and y. 2. Write two equations (two unknowns and two equations gives you enough information to solve). -The first part, "two numbers added equal 6.5" can be written as x + y = 6.5 -The second part, "two numbers multiplies equal 64" as xy = 64 3. Manipulate the equations to solve. For example: y = 64/x x + y = x + (64/x) = 6.5 4. Solve for x, and then use x to find y using either of the original formulas.
Consecutive numbers, by definition, don't differ by 17. It would have to be something like consecutive square numbers (64 and 81).
8
The numbers are 98 and 64
1 x 64, 2 x 32, 4 x 16, 8 x 8.