The sum of the prime numbers 11 and 53 equals 64.
61 and 3
They could be: 64 and 36 because 64+36 = 100 and 64-36 = 28
The numbers are 62 and 64 are two consecutive integers that equal 126.
1 & 64, 2 & 32, 4 & 16, or 8 & 8
The sum of the prime numbers 11 and 53 equals 64.
44
61 and 3
They could be: 64 and 36 because 64+36 = 100 and 64-36 = 28
The numbers are 62 and 64 are two consecutive integers that equal 126.
1 & 64, 2 & 32, 4 & 16, or 8 & 8
to factor (x2-16x+64), you need to find two number whose product is 64 and whose sum is 16. These two numbers are 8 and 8. (x2-16x+64)=(x-8)(x-8)
This problem actually has no solution. Any two numbers that will add to 6.5 will be too small to produce a multiple equal to 64. However, for problems like this in general, writing the question as a formula might help you solve it. 1. Assume the numbers are x and y. 2. Write two equations (two unknowns and two equations gives you enough information to solve). -The first part, "two numbers added equal 6.5" can be written as x + y = 6.5 -The second part, "two numbers multiplies equal 64" as xy = 64 3. Manipulate the equations to solve. For example: y = 64/x x + y = x + (64/x) = 6.5 4. Solve for x, and then use x to find y using either of the original formulas.
Consecutive numbers, by definition, don't differ by 17. It would have to be something like consecutive square numbers (64 and 81).
8
1 x 64, 2 x 32, 4 x 16, 8 x 8.
The numbers are 98 and 64