Too bad that's not x^2 - 16x + 64 which factors to (x - 8)(x - 8)
(x - 7)(x - 9)
Assuming you wish to make this equation equal zero, for x2 + 16x + 55 = 0, x = -5.
(x - 15)(x - 1)
(8 + x)2 = 64 + 16x + x2
x2 + 48x + 320
x3 + 4x2 + 16x + 64 =x2*(x + 4) + 16(x + 4) = (x + 4)*(x2 + 16) which has no further real factors.
Too bad that's not x^2 - 16x + 64 which factors to (x - 8)(x - 8)
(x - 7)(x - 9)
12
Assuming you wish to make this equation equal zero, for x2 + 16x + 55 = 0, x = -5.
No because the discriminant is less than zero.
In the absence of signs I have assumed the term in 16x and 60 are negative: ie x2 - 16x = -60 or x2 - 16x + 60 = 0 Factors of 60 which total -16 are -6 and -10, so (x - 6)(x - 10)
(x - 15)(x - 1)
(8 + x)2 = 64 + 16x + x2
x2+16x-80 = 0 (x-4)(x+20) = 0 x = 4 or x = -20
x2-16x+48 = (x-4)(x-12) when factored