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What is the solution of rational equations reducible to quadratic equation?
A quadratic equation ax2 + bx + c = 0 has the solutions x = [-b +/- sqrt(b2 - 4*a*c)]/(2*a)
Are there no real solutions if a quadratic function is 0?
If a quadratic function is 0 for any value of the variable, then that value is a solution.
How many solutions are there to the equation x2-48 equals 0?
Quadratic equations like this one usually have two solution. Sometimes they have one (so-called "double") solution. If you solve it, you'll know for sure.
Can a system of two quadratic equations have two solutions?
Yes. It can have 0, 1, or 2 solutions.
How can you have one solution in something that is quadratic?
b^2 - 4ac, the discriminant will tell you that a quadratic equation may have one real solution( discriminant = 0 ) , two real solutions( discriminant > 0 ), or no real solutions( discriminant < 0 ).
Why are there usually two solutions to a quadratic equation?
In the graph of a quadratic equation, the plotted points form a parabola. This parabola usually intersects the X axis at two different points. Those two points are also the two solutions for the quadratic equation. Alternatively: Quadratic equations are formed by multiplying two linear equations together. Each of the linear equations has one solution - multiplying two together means that the solution for either is also a solution for the quadratic equation - hence you get two possible solutions for the quadratic unless both linear equations have exactly the same solution. Example: Two linear equations : x - a = 0 x - b = 0 Multiplied together: (x - a) ( x - b ) = 0 Either a or b is a solution to this quadratic equation. Hence most often you have two solutions but never more than two and always at least one solution.
What are the degrees of quadratic equations?
A quadratic equations have a second degrees, such that Ax^2 + Bx + C = 0
What is the solution of rational equations reducible to quadratic equation?
A quadratic equation ax2 + bx + c = 0 has the solutions x = [-b +/- sqrt(b2 - 4*a*c)]/(2*a)
Why do quadratic equations where the discriminant is 0 have exactly 1 real solution?
Suppose the quadratic equation is ax^2 + bx + c = 0 and D = b^2 - 4ac is the discriminant. Then the solutions to the quadratic equation are [-b ± sqrt(d)]/(2a). Since D = 0, the both solutions are equal to -b/(2a), a single real solution.
Why are Quadratic equations which are expressed in the form of ax2 plus bx plus c 0 where a does not equal 0 may have how many solutions?
Why are Quadratic equations, which are expressed in the form of ax2 + bx + c = 0, where a does not equal 0,
Why quadratic equations have two solutions?
If the discriminant of b2-4ac of the quadratic equation is greater the 0 then it will have 2 solutions.
Do all quadratic equations have two solutions?
I may only be in 8th grade but I am absolutely positive that all quadratic equations have 2 solutions. No - They may have 0,1, or 2 answers For example, the problem x^2 + 8x +16 = 0 has only one solution -4. This is because the radical evaluates to 0 rendering the +/- sign irrelevant.
Solving quadratic equations by factoring?
(k + 1)(k - 5)= 0
Are there no real solutions if a quadratic function is 0?
If a quadratic function is 0 for any value of the variable, then that value is a solution.
When solving a quadratic equation by factoring what method is used?
Start with a quadratic equation in the form � � 2 � � � = 0 ax 2 +bx+c=0, where � a, � b, and � c are constants, and � a is not equal to zero ( � ≠ 0 a =0).
How many solutions are there to the equation x2-48 equals 0?
Quadratic equations like this one usually have two solution. Sometimes they have one (so-called "double") solution. If you solve it, you'll know for sure.
Can a system of two quadratic equations have two solutions?
Yes. It can have 0, 1, or 2 solutions.
