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What is the solution of rational equations reducible to quadratic equation?
A quadratic equation ax2 + bx + c = 0 has the solutions x = [-b +/- sqrt(b2 - 4*a*c)]/(2*a)
Are there no real solutions if a quadratic function is 0?
If a quadratic function is 0 for any value of the variable, then that value is a solution.
How many solutions are there to the equation x2-48 equals 0?
Quadratic equations like this one usually have two solution. Sometimes they have one (so-called "double") solution. If you solve it, you'll know for sure.
Can a system of two quadratic equations have two solutions?
Yes. It can have 0, 1, or 2 solutions.
What is the solution of the system of linear equations x equals 0 and y equals 0?
The solution of the system of linear equations ( x = 0 ) and ( y = 0 ) is the single point (0, 0) in the Cartesian coordinate system. This point represents the intersection of the two equations, where both variables are equal to zero. Thus, the only solution is the origin.
Why are there usually two solutions to a quadratic equation?
In the graph of a quadratic equation, the plotted points form a parabola. This parabola usually intersects the X axis at two different points. Those two points are also the two solutions for the quadratic equation. Alternatively: Quadratic equations are formed by multiplying two linear equations together. Each of the linear equations has one solution - multiplying two together means that the solution for either is also a solution for the quadratic equation - hence you get two possible solutions for the quadratic unless both linear equations have exactly the same solution. Example: Two linear equations : x - a = 0 x - b = 0 Multiplied together: (x - a) ( x - b ) = 0 Either a or b is a solution to this quadratic equation. Hence most often you have two solutions but never more than two and always at least one solution.
What are the degrees of quadratic equations?
A quadratic equations have a second degrees, such that Ax^2 + Bx + C = 0
What is the solution of rational equations reducible to quadratic equation?
A quadratic equation ax2 + bx + c = 0 has the solutions x = [-b +/- sqrt(b2 - 4*a*c)]/(2*a)
Why do quadratic equations where the discriminant is 0 have exactly 1 real solution?
Suppose the quadratic equation is ax^2 + bx + c = 0 and D = b^2 - 4ac is the discriminant. Then the solutions to the quadratic equation are [-b ± sqrt(d)]/(2a). Since D = 0, the both solutions are equal to -b/(2a), a single real solution.
Why are Quadratic equations which are expressed in the form of ax2 plus bx plus c 0 where a does not equal 0 may have how many solutions?
Why are Quadratic equations, which are expressed in the form of ax2 + bx + c = 0, where a does not equal 0,
Why quadratic equations have two solutions?
If the discriminant of b2-4ac of the quadratic equation is greater the 0 then it will have 2 solutions.
Do all quadratic equations have two solutions?
I may only be in 8th grade but I am absolutely positive that all quadratic equations have 2 solutions. No - They may have 0,1, or 2 answers For example, the problem x^2 + 8x +16 = 0 has only one solution -4. This is because the radical evaluates to 0 rendering the +/- sign irrelevant.
Solving quadratic equations by factoring?
(k + 1)(k - 5)= 0
Are there no real solutions if a quadratic function is 0?
If a quadratic function is 0 for any value of the variable, then that value is a solution.
When solving a quadratic equation by factoring what method is used?
Start with a quadratic equation in the form � � 2 � � � = 0 ax 2 +bx+c=0, where � a, � b, and � c are constants, and � a is not equal to zero ( � ≠ 0 a =0).
How many solutions are there to the equation x2-48 equals 0?
Quadratic equations like this one usually have two solution. Sometimes they have one (so-called "double") solution. If you solve it, you'll know for sure.
Can a system of two quadratic equations have two solutions?
Yes. It can have 0, 1, or 2 solutions.
