The question is impossible to answer.
Add heat and you get combustion.
Oxygen, heat and fuel :)
It's the oxygen. Since oxygen doesn't dissolve into nitrogen - air is a mixture, not a solution - you can't call it the solute and the nitrogen the solvent, which may have been the answer you thought you were going to get.
A mixture of gases that strongly resembles the major components of earth's atmosphere.
For complete proper combustion of Propane: C3H8 + 5O2 = 3CO2 + 4H2O The relative atomic weights of a molecule of Propane and Oxygen are: Propane: 3 × C + 8 × H = 3 × 12 + 8 × 1 = 44 Oxygen: 2 × O = 2 × 16 = 32 Thus a molecule of propane is 44/32 = 1⅜ times heavier than a molecule of oxygen; and the same amount (number of molecules) of propane as 24 g of oxygen is 24g × 1⅜ = 33g Each propane molecule takes 5 oxygen molecules, thus: 33 g ÷ 5 = 6 3/5 g = 6.6 g If the combustion produces the poisonous carbon monoxide instead of carbon dioxide: 2C3H8 + 7O2 = 6CO + 8H2O → propane = 33g × 2/7 = 9 3/7 g ≈ 9.4 g A complete answer is thus between 6 3/5 g (6.6g) and 9 3/7 g (9.4 g) depending upon how much carbon monoxide relative to carbon dioxide is produced by the burning - the safe amount is 6.6 g.
No. Oxygen is required for combustion. Mercury is not involved.
Yes, oxygen is required for combustion to occur. During combustion, oxygen reacts with the fuel in the presence of heat to produce energy in the form of heat and light. This chemical reaction is known as oxidation.
oxygen
Oxygen is required to sustain combustion as it is the oxidizer that allows for the chemical reaction with the fuel. The exact amount of oxygen needed depends on the type of fuel being burned, as different fuels have different oxygen requirements for combustion. In general, combustion requires a sufficient supply of oxygen to ensure complete oxidation of the fuel.
The balanced chemical equation for the combustion of propane is: C3H8 + 5 O2 -> 3 CO2 + 4 H2O. This means that 5 moles of oxygen are required to completely combust 1 mole of propane. Therefore, 20 moles of oxygen would be produced from the complete combustion of 4 moles of propane.
Oxygen supports combustion by reacting with a fuel at high temperatures to produce heat and light energy. The oxygen in the air combines with the fuel, breaking bonds and releasing energy in the form of heat, which sustains the combustion process.
Yes, more oxygen is used in incomplete combustion compared to complete combustion because incomplete combustion results in the partial burning of the fuel, leading to the formation of more byproducts like carbon monoxide and soot. This requires additional oxygen to combine with these byproducts, using up more oxygen overall.
Oxygen is required for the combustion of fossil fuels. During combustion, the carbon and hydrogen in the fossil fuels react with oxygen to produce carbon dioxide, water, and heat energy.
When propane is completely burnt, it reacts with oxygen to produce carbon dioxide and water vapor, releasing energy in the form of heat. This chemical reaction is known as combustion.
The balanced chemical equation for the combustion of propane is: C3H8 + 5 O2 -> 3 CO2 + 4 H2O This indicates that 5 moles of oxygen are required to fully combust 1 mole of propane.
Excess supply of oxygen ensures that all available fuel molecules can react with oxygen molecules, resulting in complete combustion. This process provides sufficient energy for all fuel molecules to break down fully into carbon dioxide and water without leaving any unburned residue.
what is the mass in grams of oxygen, is needed to complete combustion of 6 L of methane?