Unless it's in a ship that is accelerating, a simole pendulum will not swing in free
space. If it's in a ship that's accelerating, its period will depend on the magnitude
of the acceleration.
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Time period and length of a pendulum are related by: T = 2(pi)(L).5(g).5 so putting in the values and solving for g yields a result of : g = 9.70 ms-2
An Ellicott pendulum is a temperature compensated clock pendulum. The metal rod of a pendulum changes its length with temperature. The consequence is, that a colder pendulum swings faster (the rod is shorter) and a warm pendulum swings slower (longer rod). The Ellicott pendulum compensates this temperature error of the pendulum. It consists of a steele rod and two brass rods, wich are connectet in one point above the pendulum bob. Brass has a higher temperature coefficient than steele. On the free end of the three rods, a special lever mechanism, controlled by the lenght difference of the rods, lifts the pendulum bob up, when the length of the rods grows. The bob stays at its position and the period of the pendulum is without temperature influence. See also http://commons.wikimedia.org/wiki/File:Ellicott_pendulum.png
A Foucault pendulum is a pendulum with a large length which is free to oscillate in any vertical plane. At the equator, the plane of oscillation remains fixed relative to the earth. Elsewhere, the plane of oscillation rotates, at a speed that is related to the latitude of the location. In Paris, where Foucault's pendulum is located, the plane of the pendulum's oscillation moves at approx 11 degrees per hour. This movement can be used to tell the time.
M^1 L^1 T^-2 A^-2 ARE THE DIMENSIONS OF PERMEABLITY OF FREE SPACE AND CALCULATED USING FORMULAF = Bqv THEN I.E. B=F/qv THEN BY B = µ0NI/L
-- look up the electrostatic permittivity of free space -- look up the magnetic permeability of free space -- multiply them -- take the square root of the product -- take the reciprocal of the square root The number you have is the speed of light in a vacuum.