Q: What would be the fraction of 1 triangles in the rhombus?

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Nope sorry, a Rhombus will be split into 2 isosceles triangles and 1 equilateral triangle.

1/3

It is 1/2

1/2

If you multiply the lengths of the two diagonals, and divide by 2, you get the area of a rhombus. How does this work: Call the diagonals A & B for clarity. Diagonal A will split the rhombus into 2 congruent triangles. Looking at one of these triangles, its base is the diagonal A, and its height is 1/2 of diagonal B. So the area of one of the triangles is (1/2)*base*height = (1/2)*A*(B/2) = A*B/4. The other triangle has the same area, so the two areas together make up the whole rhombus = 2*(A*B/4) = A*B/2.

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Nope sorry, a Rhombus will be split into 2 isosceles triangles and 1 equilateral triangle.

1 rhombus 4-5 triangles

1/3

It is 1/2

Two equilateral triangles can form a rhombus- it can also be formed by using a higher number of isosceles triangles.

1/2

Suppose the parallel sides of the trapezium are a and b units where a < b. Then the fraction of the area of the trapezium that is the rhombus is a/[(a+b)/2] = 2a/(a+b).

If you multiply the lengths of the two diagonals, and divide by 2, you get the area of a rhombus. How does this work: Call the diagonals A & B for clarity. Diagonal A will split the rhombus into 2 congruent triangles. Looking at one of these triangles, its base is the diagonal A, and its height is 1/2 of diagonal B. So the area of one of the triangles is (1/2)*base*height = (1/2)*A*(B/2) = A*B/4. The other triangle has the same area, so the two areas together make up the whole rhombus = 2*(A*B/4) = A*B/2.

A decimal is a way of representing a number in such a way that the place value of each digit is ten times that of the digit to its right. A decimal representation does not require a decimal point. A decimal form has nothing to do with rhombuses and triangles. The best I can think of is 1 rhombus = 2 triangles.

The area of a rhombus is half the product of the diagonals. A = 1/2bc. The diagonals (of length b and c) intersect at right angles and form two congruent triangles either side of one chosen diagonal. The area of one such triangle is 1/2b x 1/2c (area of a triangle = 1/2 base x height). The area of both triangles and therefore the area of the rhombus is 2(1/2b x 1/2c) = 1/2bc.

That all depends on the dimensions of the trapezoid you're working with.

There are an infinite number of options. Even sticking with polygons with sides of the same measure, a hexagon can be made from 6 equilateral triangles, or 4 eq triangles and a 60 degree rhombus, or 2 eq triangles and 2 60-deg rhombi, or 3 60-deg rhombi. Each of the equilateral triangle could be made from smaller shapes. Eg four equilateral mini-triangles to make 1 triangle. Or 2 mini-triangles and 1 mini-rhombus or 2 60-deg mini-rhombi. And then each of those mini triangles could be made up of smaller micro-shapes. And so on ...