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The area of a rhombus is half the product of the diagonals. A = 1/2bc.

The diagonals (of length b and c) intersect at right angles and form two congruent triangles either side of one chosen diagonal.

The area of one such triangle is 1/2b x 1/2c (area of a triangle = 1/2 base x height).

The area of both triangles and therefore the area of the rhombus is 2(1/2b x 1/2c) = 1/2bc.

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Q: How can you find the area of a rhombus using diagonals?
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Find the area of a rhombus with diagonals that measure 8 and 10?

Find the area of a rhombs with diagonals that measure 8 and 10.


How do you find the measures of a rhombus with two diagonals?

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If side is given too, then you can find area with one diagonal. As diagonals bisect each other in a rhombus at 90°, Using Pythogoras Theorem: (Half d1)² = (side)² - (Half d2)²


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How do you find the length of the rhombus when the length of the diagonals are given?

By dividing itImproved Answer:-A rhombus has 4 equal sides and its diagonals bisect each other at 90 degrees thus forming 4 equal right angle triangles and by using Pythagoras' theorem any of the 4 equal sides can be found.