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The area of a rhombus is half the product of the diagonals. A = 1/2bc.
The diagonals (of length b and c) intersect at right angles and form two congruent triangles either side of one chosen diagonal.
The area of one such triangle is 1/2b x 1/2c (area of a triangle = 1/2 base x height).
The area of both triangles and therefore the area of the rhombus is 2(1/2b x 1/2c) = 1/2bc.
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The diagonals of the rhombus are in the ratio 3 4 the perimeter of the rhombus is 40cm find the lengths of the sides and of the diagonals?
The length of the sides of the rhombus are 10cm, as a rhombus has equal sides. since the diagonals of a rhombus are perpendicular, ratio of side of rhombus to 1/2 a diagonal to 1/2 of another diagonal is 5:4:3 (pythagorean thriple), hence ratio of side of rhombus to 1 diagonal to another diagonal is 5:8:6. since 5 units = 10cm 8 units = 16cm 6 units = 12cm and there are your diagonals.
Find the area of a rhombus?
A = baWhere A = areab = length of the basea = altitude (height).
What is the area of a rhombus with a perimeter of 20 meters and a diagonal of 8 meters?
Constructing the figure, we find the other diagonal to have length 10.The area of the rhombus would thus be 10x8x0.5=40
Find the area of a rhombus whose one side is 13 cm and the altitude is 10 cm?
130 is the area.
Do you add or multiply length and width?
If you want to find the area of a rectangle (inclusively a square), rhombus, or parallelogram, you multiply.
