The area of a rhombus is half the product of the diagonals. A = 1/2bc.
The diagonals (of length b and c) intersect at right angles and form two congruent triangles either side of one chosen diagonal.
The area of one such triangle is 1/2b x 1/2c (area of a triangle = 1/2 base x height).
The area of both triangles and therefore the area of the rhombus is 2(1/2b x 1/2c) = 1/2bc.
The length of the sides of the rhombus are 10cm, as a rhombus has equal sides. since the diagonals of a rhombus are perpendicular, ratio of side of rhombus to 1/2 a diagonal to 1/2 of another diagonal is 5:4:3 (pythagorean thriple), hence ratio of side of rhombus to 1 diagonal to another diagonal is 5:8:6. since 5 units = 10cm 8 units = 16cm 6 units = 12cm and there are your diagonals.
A = baWhere A = areab = length of the basea = altitude (height).
Constructing the figure, we find the other diagonal to have length 10.The area of the rhombus would thus be 10x8x0.5=40
130 is the area.
If you want to find the area of a rectangle (inclusively a square), rhombus, or parallelogram, you multiply.
Find the area of a rhombs with diagonals that measure 8 and 10.
That will depend on the lengths of the diagonals of the rhombus which are of different lengths and intersect each other at right angles but knowing the lengths of the diagonals of the rhombus it is then possible to work out its perimeter and area.
54
If side is given too, then you can find area with one diagonal. As diagonals bisect each other in a rhombus at 90°, Using Pythogoras Theorem: (Half d1)² = (side)² - (Half d2)²
That is one of the ways of finding the area of a rhombus. The area is half the product of the diagonals. In this case, 1/2 of 7 x 4.4 or .154. You can also find the area of a rhombus by using one side as the base and finding an altitude for that base and multiplying them. There is a third way using trigonometry.
If those are its diagonals then area is: 0.5*10*11 = 55 square units other wise use Pythagoras to find diagonal EG because area of a rhombus is 0.5 times the product of its diagonals.
The diagonals are not equal in length but thet bisect each other at 90 degrees
1/2 x 8 x 7 = 28cm2
The answer depends on the measure of WHAT! Side length, angles, length of diagonals, area? And the answers to these depend on what information is given.
To find the value of x in a rhombus, use these properties. All sides of a rhombus are the same length. Opposite angles of a rhombus are the same size and measure. Intersection of the diagonals of a rhombus form right angles. Sides are perpendicular. The diagonals of rhombus bisect each other. Adjacent angles add up to 180 degrees.
The diagonals of a rhombus (not rombhus) bisect one another at right angles. The sides of the rhombus form the hypotenuses of triangles whose other sides are half the diagonals. So use Pythagoras.
By dividing itImproved Answer:-A rhombus has 4 equal sides and its diagonals bisect each other at 90 degrees thus forming 4 equal right angle triangles and by using Pythagoras' theorem any of the 4 equal sides can be found.