The area of a rhombus is half the product of the diagonals. A = 1/2bc.
The diagonals (of length b and c) intersect at right angles and form two congruent triangles either side of one chosen diagonal.
The area of one such triangle is 1/2b x 1/2c (area of a triangle = 1/2 base x height).
The area of both triangles and therefore the area of the rhombus is 2(1/2b x 1/2c) = 1/2bc.
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The length of the sides of the rhombus are 10cm, as a rhombus has equal sides. since the diagonals of a rhombus are perpendicular, ratio of side of rhombus to 1/2 a diagonal to 1/2 of another diagonal is 5:4:3 (pythagorean thriple), hence ratio of side of rhombus to 1 diagonal to another diagonal is 5:8:6. since 5 units = 10cm 8 units = 16cm 6 units = 12cm and there are your diagonals.
A = baWhere A = areab = length of the basea = altitude (height).
Constructing the figure, we find the other diagonal to have length 10.The area of the rhombus would thus be 10x8x0.5=40
130 is the area.
If you want to find the area of a rectangle (inclusively a square), rhombus, or parallelogram, you multiply.