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Can four lines have seven intersection points?
No. In plane geometry, two lines can intersect at at most one point. This means that for n points, the maximum number of intersections is limited by the number of pairs of lines. For lines a,b,c,d, there are six pairs: (a,b), (a,c), (a,d), (b,c), (b,d), (c,d). So four lines can have at most six intersections.
Find the distance between lines y plus mx plus c and y equals mx plus b?
y = mx + c y = mx + b We see that the lines have the same slope m. If the lines have slopes with the same sign, then the lines are parallel. Soppose that the slope is positive, m > 0. Case 1: If c > 0, b> 0, and c > b, or c < 0, b < 0, and c < b, then we have to work in the same way to find the distance between lines, which is also the same distance. Let work for the first possibility where c > 0, b > 0, and c > b. If we draw the lines, we see that from the interception of the lines with x and y-coordinate axis, are formed two similar right triangles on the second quadrant. The bigger triangle vertices are (0, c), (0, 0), and (-c, 0) The midpoint of the hypotenuse is (-c/2, c/2). The distance between the origin and the midpoint is (c√2)/2. √[(-c/2)2 + (c/2)2] = √(c2/4 + c2/4) = √ (2c2/4) = (c√2)/2 The smaller triangle vertices are (0, b), (0, 0), and (-b, 0) The midpoint of the hypotenuse is (-b/2, b/2). The distance between the origin and the midpoint is (b√2)/2. √[(-b/2)2 + (b/2)2] = √(b2/4 + b2/4) = √ (2b2/4) = (b√2)/2 The distance between the lines is (√2)/2)(c - b). (c√2)/2 - (b√2)/2 = (√2)/2)(c - b) Case 2: If c > 0, b< 0 or c < 0, b > 0. If we draw the lines, we see that from the interception of the lines with x and y-coordinate axis are formed two similar right triangles on the second and fourth quadrant. In this case the distance between lines is (√2)/2)(c + b). If the slope is negative for both lines, then we find the same result as above, but the formed right triangles are in the first and third quadrant. If the lines have slopes with different sign, then the lines intersect.
How many lines are determined by coplanar points a b c and d?
4*3/2 = 6 lines.
How is the Transitive Property of Parallel Lines similar to the Transitive Property of Congruence?
If A ~ B and B ~ C then A ~ C. The above statement is true is you substitute "is parallel to" for ~ or if you substitute "is congruent to" for ~.
What are the diagonals in a quadrilateral?
The diagonals in a quadrilateral are the (usually imaginary) straight lines that go through the inside of the shape from one vertex to another. For example, say you have a square (a quadrilateral) consisting of points A, B, C, and D. They are all connected on edges going A to B, B to C, C to D, and D to A. Envisioning this shape in your mind, you would likely imagine the inside of the square being blank. There would be two diagonals in a shape like this (as well as in every quadrilateral) being the lines going from A, through the center of the square, to C, and the other being the line going from B, through the center, to D.
Rhyme scheme of madam and the rent man?
The rhyme scheme of "Madam and the Rent Man" is AABB. This means that the first and second lines rhyme with each other, and the third and fourth lines rhyme with each other.
Which of the following statements is a good definition a Skew lines are lines that do not intersect b Parallel lines are lines that do not intersect c A square is a rectangle with four congruent side?
b & c
Points A B and C are collinear How many lines are determined by A B and C?
# 1
Can four lines have seven intersection points?
No. In plane geometry, two lines can intersect at at most one point. This means that for n points, the maximum number of intersections is limited by the number of pairs of lines. For lines a,b,c,d, there are six pairs: (a,b), (a,c), (a,d), (b,c), (b,d), (c,d). So four lines can have at most six intersections.
Points a b c and d are coplanar b c and d are collinear not a how many lines are determined by a b c and d?
5 its 4
Find the distance between lines y plus mx plus c and y equals mx plus b?
y = mx + c y = mx + b We see that the lines have the same slope m. If the lines have slopes with the same sign, then the lines are parallel. Soppose that the slope is positive, m > 0. Case 1: If c > 0, b> 0, and c > b, or c < 0, b < 0, and c < b, then we have to work in the same way to find the distance between lines, which is also the same distance. Let work for the first possibility where c > 0, b > 0, and c > b. If we draw the lines, we see that from the interception of the lines with x and y-coordinate axis, are formed two similar right triangles on the second quadrant. The bigger triangle vertices are (0, c), (0, 0), and (-c, 0) The midpoint of the hypotenuse is (-c/2, c/2). The distance between the origin and the midpoint is (c√2)/2. √[(-c/2)2 + (c/2)2] = √(c2/4 + c2/4) = √ (2c2/4) = (c√2)/2 The smaller triangle vertices are (0, b), (0, 0), and (-b, 0) The midpoint of the hypotenuse is (-b/2, b/2). The distance between the origin and the midpoint is (b√2)/2. √[(-b/2)2 + (b/2)2] = √(b2/4 + b2/4) = √ (2b2/4) = (b√2)/2 The distance between the lines is (√2)/2)(c - b). (c√2)/2 - (b√2)/2 = (√2)/2)(c - b) Case 2: If c > 0, b< 0 or c < 0, b > 0. If we draw the lines, we see that from the interception of the lines with x and y-coordinate axis are formed two similar right triangles on the second and fourth quadrant. In this case the distance between lines is (√2)/2)(c + b). If the slope is negative for both lines, then we find the same result as above, but the formed right triangles are in the first and third quadrant. If the lines have slopes with different sign, then the lines intersect.
What would a be if a was b and b was c and c was a?
C
Number of lines to connect 5 routers as point to point simplex line?
10 Nodes A B C D E A-B B-C C-D D-E A-C A-D E-B E-C E-A B-D
How many RER lines are there in Paris?
There are 5 RER lines in Paris: A, B, C, D, and E.
What are vertical horizontal and diagonal lines?
a...................b . . . . . c...................d a to c = vertical line a to b = horizontal line a to d = diagonal line
What is the theoretical maximum channel capacity of traditional telephone lines?
C = B * log2(1 + SNR) C= channel capacity B= Bandwidth , telephone lines have a usable range of around 3400Hz = =
How many lines are determined by coplanar points a b c and d?
4*3/2 = 6 lines.
