9 or 19 or 29 or 39 or 49 or 59 and so on and so forth. You could also add negative one, negative eleven, etc.
you would add 8-making the number 550.550 divided by 10 is 55
You would add 8 - making the number 550. 550 divided by 10 is 55.
To find the number that can be added to 368 to make it divisible by 27, you need to first determine the remainder when 368 is divided by 27. You can do this by finding the modulus of 368 divided by 27, which is 17. To make 368 divisible by 27, you need to add the difference between 27 and the remainder (27 - 17 = 10). Therefore, you would need to add 10 to 368 to make it divisible by 27.
26.1 is 10% of 261.
Any number that is divisible by 10 is an even number and hence divisible by 2 also. It can also be stated that because 10 is divisible by 2, all numbers divisble by 10 are also divisible by 2.
To make 243 divisible by 10, we need to find the nearest multiple of 10. The nearest multiple of 10 less than 243 is 240. To make 243 divisible by 10, we need to add 240 + 3, which equals 243. Therefore, we need to add 3 to 243 to make it divisible by 10.
you would add 8-making the number 550.550 divided by 10 is 55
Well, honey, if you want to make 243 divisible by 10, you need to add 7 to it. Why 7, you ask? Because 243 + 7 = 250, and 250 is divisible by 10. So, go ahead and sprinkle that 7 on top like the cherry on a sundae.
You would add 8 - making the number 550. 550 divided by 10 is 55.
To find the number that can be added to 368 to make it divisible by 27, you need to first determine the remainder when 368 is divided by 27. You can do this by finding the modulus of 368 divided by 27, which is 17. To make 368 divisible by 27, you need to add the difference between 27 and the remainder (27 - 17 = 10). Therefore, you would need to add 10 to 368 to make it divisible by 27.
To find out if 640 is divisible by 3, we will add up the numbers that make 640 as follows: 6 + 4 + 0 = 10 We know that if the sum of the numbers that make up 640 is divisible by 3, then 640 is divisible by 3. Since 10 is NOT divisible by 3, 640 is also NOT divisible by 3. Thus, the answer to the question "Is 640 divisible by 3?" is NO. If you divide 640 by 3, you get 213.3333333.
26.1 is 10% of 261.
The lowest number you could add to make it divisible by 10, 2, and 5 would be 7. 23 + 7 = 30 30/10 = 3 30/2 = 15 30/5 = 6 Also, technically, you could add (-3) to make 20. 23 + (-3) = 20 20/10 = 2 20/2 = 10 20/5 = 4 Basically, you could add any number to 23 that would get a multiple of 10, since 2 and 5 are both factors of 10 to begin with.
Because the quotient of 261/10 is not an integer.
you must add 10 368+10=378 378/27=14 If you divide 368 by 27, you get 13 and remainder 17. So you add 10.
261 of them.
Any number that is divisible by 10 is an even number and hence divisible by 2 also. It can also be stated that because 10 is divisible by 2, all numbers divisble by 10 are also divisible by 2.