If d = 16*t^2 then there is no significant air resistance.
At 40 mph, a vehicle's reaction distance, which is the distance covered from the moment a driver perceives a hazard to the moment they begin to brake, is approximately 44 feet. This calculation assumes a reaction time of about 1.5 seconds. Therefore, at this speed, a driver travels about 58 feet per second, leading to the reaction distance being a key factor in overall stopping distance.
Time = Distance/Speed = 13.33 hours approx. This assumes that an average speed of 55 mph can be maintained for that length of time after allowing for comfort stops, fuelling stops etc.
A Shapeshifter.
The vertical distance an object falls can be calculated using the formula ( d = \frac{1}{2} g t^2 ), where ( d ) is the distance fallen, ( g ) is the acceleration due to gravity (approximately ( 9.81 , \text{m/s}^2 ) on Earth), and ( t ) is the time in seconds that the object has been falling. This formula assumes that the object is falling freely under the influence of gravity, with no air resistance.
Time = Distance/Speed = 3000/4 = 750 hours = 31.25 days so just over a month. But that assumes non-stop walking for a month - which is not at all realistic.
distance = speed x time.This assumes a constant speed.distance = speed x time.This assumes a constant speed.distance = speed x time.This assumes a constant speed.distance = speed x time.This assumes a constant speed.
The mutual forces of attraction between him and the Earth will not change, no matter where he goes, how he moves, or what position he assumes, as long as he remains at roughly the same distance from the center of the Earth.
Time = Distance/Speed = 736/65 = 11.323 hours (approx).That assumes that you can maintain the speed for that length of time without stoppages for comfort, rest, food or fuel.Time = Distance/Speed = 736/65 = 11.323 hours (approx).That assumes that you can maintain the speed for that length of time without stoppages for comfort, rest, food or fuel.Time = Distance/Speed = 736/65 = 11.323 hours (approx).That assumes that you can maintain the speed for that length of time without stoppages for comfort, rest, food or fuel.Time = Distance/Speed = 736/65 = 11.323 hours (approx).That assumes that you can maintain the speed for that length of time without stoppages for comfort, rest, food or fuel.
Kinetic molecular theory assumes that gases consist of particles (atoms or molecules) in constant random motion. It also assumes that gas particles are small compared to the distance between them. Additionally, the theory assumes that gas particles are in continuous, rapid, and random motion.
get a parachute and equip it using RT trigger. Then when in the air, press A button at any time to open then steer with the left analogue stick. ^^ Stupid xbot does typical xbot thing and assumes everyone plays Xbox Three $hitty. Press R2 to equip parachute and X to activate while falling. ^^ Stupid PS3 does typical PS3 thing and assumes everyone plays Playshit 3. Press LMB to equip parachute and LEFT SHIFT to activate while falling.
The formula, distance = speed x time, or speed = distance / time, assumes constant speed. If the speed changes, then the formula speed = distance / time will give you the average speed over the time period. To get the instantaneous speed in this case, you must divide distance / time for a very short time interval.
The employer usually assumes the role of the buyer, and the employee assumes the role of the seller.
The shortest distance driving is 970 km.The distance has been calculated as being: 686 kilometres (429 miles) by air.The above assumes that you mean VANCOUVER BC, CANADA, and not VANCOUVER WA, USA.
assumes fact
Time = Distance/Speed = 18.18 hours. But that assumes no comfort breaks, no stops for food or drink or fuel, or rest.
You can only know the distance for sure if acceleration or deceleration is constant. Add the start and end velocities and divide by two and then multiply by the time to get your distance.
The total EW distance is 8 - 2 = 6 km.The total NS distance is 5 kmTherefore, total distance from the start is sqrt(62 + 52) = sqrt(36 + 25) = sqrt(61) =7.8 km (approx).The answer assumes that the boat is sufficiently far from the poles so that the various stages of its travel is along perpendicular lines.The total EW distance is 8 - 2 = 6 km.The total NS distance is 5 kmTherefore, total distance from the start is sqrt(62 + 52) = sqrt(36 + 25) = sqrt(61) =7.8 km (approx).The answer assumes that the boat is sufficiently far from the poles so that the various stages of its travel is along perpendicular lines.The total EW distance is 8 - 2 = 6 km.The total NS distance is 5 kmTherefore, total distance from the start is sqrt(62 + 52) = sqrt(36 + 25) = sqrt(61) =7.8 km (approx).The answer assumes that the boat is sufficiently far from the poles so that the various stages of its travel is along perpendicular lines.The total EW distance is 8 - 2 = 6 km.The total NS distance is 5 kmTherefore, total distance from the start is sqrt(62 + 52) = sqrt(36 + 25) = sqrt(61) =7.8 km (approx).The answer assumes that the boat is sufficiently far from the poles so that the various stages of its travel is along perpendicular lines.