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When an error of 1 percent is made in the length of a square the percentage error in the area of square will be?
The percentage error in the area of the square will be twice the percentage error in the length of the square. This is because the error in the length affects both the length and width of the square, resulting in a compounded effect on the area. Therefore, if there is a 1 percent error in the length, the percentage error in the area would be 2 percent.
When an error 1 percent is made in the length and breadth of a rectangle the percent in the area of rectagle will be?
1
What if percent error is greater than zero?
It means that the measured value is greater than the true value. Unless the experiment can be made error-free, that should happen around half the time.
What shape can be made by combining a square and a triangle?
An irregular* pentagon *means that the sides are not all the same length
What will be the time period of a pendulum if it's length is made one fourth of it?
Since the period of a simple pendulum (for short swings) in proportional to the square root of its length, then making the length one quarter of its original length would make the period one half of its original period.Periodapproximately = 2 pi square root (length/acceleration due to gravity)
When an error of 1 percent is made in the length of a square the percentage error in the area of square will be?
The percentage error in the area of the square will be twice the percentage error in the length of the square. This is because the error in the length affects both the length and width of the square, resulting in a compounded effect on the area. Therefore, if there is a 1 percent error in the length, the percentage error in the area would be 2 percent.
When an error of 1 percent is made in the length of square the percentage error in the area of a square will be?
1% off
When an error of 1 percent is made in the length of a square the percentage of error in the area of a square will be?
area= side^2 let the symbol # denote error in measurement #area/area= 2(#length/length) #area/area*100= 2(#length/length)*100 percent error in area= 2*percent error in length=2% 2 per cent
When an error of 1 percent is made in the length of square the percentage error in area of a square will be?
Well, darling, when you make a 1% error in the length of a square, the percentage error in the area is technically 2%. It's simple math, honey. Just double the percentage error in length to get the percentage error in area. Easy peasy lemon squeezy.
When an error 1 percent is made in the length and breadth of a rectangle the percent in the area of rectagle will be?
1
Can the answer of a percent error problem be 300?
Yes, your percent error can be over 100%. This means that somewhere during your experiment you made a big error.
A figure is made up of square with a side length of 8 cm and a circle inside it with the same diameter as the length of the square. Find the area of the composite figure. Show your solution?
64
What is a percent error?
It is a measure measurement of the amount of error made in an experiment. It is obtained by comparing the actual result, with the result gotten from the experiment. % error = [(experimental value - true value) / true value] x 100
What if percent error is greater than zero?
It means that the measured value is greater than the true value. Unless the experiment can be made error-free, that should happen around half the time.
What shape can be made by combining a square and a triangle?
An irregular* pentagon *means that the sides are not all the same length
When an error of 1 percent is made in the length and breadth of a rectangle the percent of error in the area of a rectangle will be?
You haven't said whether the error is 1% in each dimension, or 1/2% in each dimension, or whether the measurement is 1% too small, or whether it's 1% too big. In the arcane jargon of mathematics, this question would be characterized as 'sloppy'. -- If both the length and width are reported to be 1% shorter than they actually are, then the area will be calculated as 1.99% too small. -- If both the length and width are reported to be 1% longer than they actually are, then the area will be calculated as 2.01% too large. -- If one dimension is measured 1% too short and the other dimension is measured 1% too long, then the area will be calculated as 0.01% too small.
What will be the time period of a pendulum if it's length is made one fourth of it?
Since the period of a simple pendulum (for short swings) in proportional to the square root of its length, then making the length one quarter of its original length would make the period one half of its original period.Periodapproximately = 2 pi square root (length/acceleration due to gravity)
