area= side^2
let the symbol # denote error in measurement
#area/area= 2(#length/length)
#area/area*100= 2(#length/length)*100
percent error in area= 2*percent error in length=2%
2 per cent
Well, darling, when you make a 1% error in the length of a square, the percentage error in the area is technically 2%. It's simple math, honey. Just double the percentage error in length to get the percentage error in area. Easy peasy lemon squeezy.
what is the number supposed to be if you git 7 cm? Percent error is the percentage that you're incorrect by, so you need another measurement. to do it, you find the difference and then divide by the original so (7-x)/true value then multiply by 100 to get percentage.
no
Yes, your percent error can be over 100%. This means that somewhere during your experiment you made a big error.
When Percent Equal 100%
The percentage error in the area of the square will be twice the percentage error in the length of the square. This is because the error in the length affects both the length and width of the square, resulting in a compounded effect on the area. Therefore, if there is a 1 percent error in the length, the percentage error in the area would be 2 percent.
1% off
Well, darling, when you make a 1% error in the length of a square, the percentage error in the area is technically 2%. It's simple math, honey. Just double the percentage error in length to get the percentage error in area. Easy peasy lemon squeezy.
The error in its area is then 2 percent....
what is the percent error of 12m
You think probable to percent error.
.229/.225 = 1.0178 percent error = (1.0178 - 1) times 100 to get to percent = .0178 x 100 = 1.78%
A percent error depends on the size of the measurement as well as the error itself. It's very intuitive to think about: If you're measuring a piece of paper and you're off by 4 cm, you'll have problems; if you're measuring the moon, that's nothing. A bigger percent error is a bigger deal to an engineer. You can calculate it the same way as any percentage: Divide the error by the total length of the measurement, then multiply by 100 to convert it from a proportion to a percentage.
The Percent error for this problem right here is 3% .
Percent error refers to the percentage difference between a measured value and an accepted value. To calculate the percentage error for density of pennies, the formula is given as: percent error = [(measured value - accepted value) / accepted value] x 100.
You do not add the percentage error but the actual error.
The difference: -age(hey, it's not wrong...)In general, probably not - percent and percentage are often used interchangeably. The context of use may warrant a difference though, if strict semantics are being followed:"Percent error" would refer to the the maximum potential difference between what a value could be, and what that value is stated to be. "Percentage error", in such a scenario, would refer to an erroneous percentage (as in, the percentage itself is incorrect).