If it is a 2-dimensional figure then it is proportional.
The perimeter, being a linear measure, also changes by a factor of 3.
If you are asking how the perimeter of an object changes if the whole object is proportionally changed: The perimeter changes by the same factor as the change in proportion of the whole object. For example: given a square that is 2 units by 2 units, changed by a factor of four, the new size would be 8 units by 8 units. The original perimeter was 2+2+2+2=8. The new perimeter is 8+8+8+8=32. So, multiplying the original perimeter, 8, by the factor of proportional change, 4, we get 8x4=32. For any object, multiply the original perimeter by the factor of proportional change to arrive at the new perimeter.
The absolute value of the perimeter doesn't change, only the unit value which increases by a factor of 3.
The area changes by the square of the same factor.
Any area is proportional to the square of its linear dimensions. So, in order to triple the surface area of a cone, you would have to multiply its radius and height each by sqrt(3) = 1.732 (rounded). It could be done by increasing only the radius, or only the height, but then the proper factor would depend on the other dimension that isn't being changed.
The perimeter, being a linear measure, also changes by a factor of 3.
If you are asking how the perimeter of an object changes if the whole object is proportionally changed: The perimeter changes by the same factor as the change in proportion of the whole object. For example: given a square that is 2 units by 2 units, changed by a factor of four, the new size would be 8 units by 8 units. The original perimeter was 2+2+2+2=8. The new perimeter is 8+8+8+8=32. So, multiplying the original perimeter, 8, by the factor of proportional change, 4, we get 8x4=32. For any object, multiply the original perimeter by the factor of proportional change to arrive at the new perimeter.
Perimeter is proportional to the linear dimensions, so it increases by 3x .Area is proportional to (linear dimensions)2, so it increases by 9x .
The absolute value of the perimeter doesn't change, only the unit value which increases by a factor of 3.
The area changes by the square of the same factor.
if all 3 dimensions increase b factor of 7 then volume changes by 7 cubed or a factor of 343
Ohm's Law: V = I*R, so Voltage and Current are directly proportional and a change in voltage will result in a proportional change in current. (The current reduces by the same factor)
An independent variable is any factor that can change or be changed in an experiment. It is what the experimenter manipulates to observe its effect on the dependent variable.
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Any area is proportional to the square of its linear dimensions. So, in order to triple the surface area of a cone, you would have to multiply its radius and height each by sqrt(3) = 1.732 (rounded). It could be done by increasing only the radius, or only the height, but then the proper factor would depend on the other dimension that isn't being changed.